Answer:
I believe it is they will weigh the same
Explanation:
Center of gravity is the axis on which the mass rotates evenly if I remember correctly from AP Physics
Answer:
10.4 m/s
Explanation:
First, find the time it takes for the projectile to fall 6 m.
Given:
y₀ = 6 m
y = 0 m
v₀ = 0 m/s
a = -9.8 m/s²
Find: t
y = y₀ + v₀ t + ½ at²
(0 m) = (6 m) + (0 m/s) t + ½ (-9.8 m/s²) t²
t = 1.11 s
Now find the horizontal position of the target after that time:
Given:
x₀ = 6 m
v₀ = 5 m/s
a = 0 m/s²
t = 1.11 s
Find: x
x = x₀ + v₀ t + ½ at²
x = (6 m) + (5 m/s) (1.11 s) + ½ (0 m/s²) (1.11 s)²
x = 11.5 m
Finally, find the launch velocity needed to travel that distance in that time.
Given:
x₀ = 0 m
x = 11.5 m
t = 1.11 s
a = 0 m/s²
Find: v₀
(11.5 m) = (0 m) + v₀ (1.11 s) + ½ (0 m/s²) (1.11 s)²
v₀ = 10.4 m/s
It's sort of like force so say you said dog then you used like force or impulse
Answer: 4.0024 x 10^ -11 m or 0.040024 nm
Explanation:
λ = h c/ΔE
λ = wave lenght
h = 6.626 x 10 ^ -34 m² kg /s = planck constant
ΔE = 31 keV potential ( 1 keV = 1.6021 x 10^-16J)
c = velocity of light = 3 x 10⁸ m/s
substitute gives
λ = <u>6.626 x 10 ^ -34 m² kg /s x 3 x 10⁸ m/s</u> = 4.0024 x 10^ -11 m
31 x 1.6021x10^-16 J
Answer:
<h2>90 J</h2>
Explanation:
The work done by an object can be found by using the formula
workdone = force × distance
From the question we have
workdone = 30 × 3
We have the final answer as
<h3>90 J</h3>
Hope this helps you
