The answer is 100.
The formula is KE = 1/2mv^2
Then you plug in 50 to the m
And 2 to the v . That’s how I got 100 .
Hope this helps
Answer:
a

b

Explanation:
From the question we are told that
The initial position of the particle is 
The initial velocity of the particle is 
The acceleration is 
The time duration is 
Generally from kinematic equation

=> 
=> 
Generally from kinematic equation

Here s is the distance covered by the particle, so

=> 
Generally the final position of the particle is

=> 
=> 
Answer:
Shaft
coiled
generators
Kinetic
Electrical
Explanation:
By using moving shaft and coiled wire together, electric generators create electricity. Electric generators essentially convert kinetic energy (the energy of motion) into electric energy.
I’m going to assume initial velocity is 0.
Use Newton’s second law:
F = m•a
F/m = a
14.0/32.5kg= 28/65 m/s^2
Use constant SUVAT acceleration formulae:
S- displacement - what we need to find out
U - initial velocity - 0
V
A - 28/65 m/s^2
T - 10 seconds
S = ut + 1/2at^2
Since u = 0
S = 1/2at^2
1/2• 28/65 • 10^2 = 21.5metres~
Answer is 21.5 metres
~Hoodini, here to help.