Answer: The force acting on the proton of charge 1.5 x10-19 C moving with velocity 1.5 x10-19 C under the influence of a magnetic field of 0.7 T will be 3.15×10^-13 N.
Explanation: To find the answer we need to know more about the Lorentz magnetic force.
<h3>What is the Lorentz magnetic force acting on the proton?</h3>
- Consider a proton of charge q moving with a velocity v in a magnetic field, then the Lorentz magnetic force exerted on the proton can be expressed as,
F= q (v× B)
where,
is the angle between v and B.
- In the question, it is given that,
because, from the question it is clear that the proton is moving along x axis and the magnetic field is along the y axis.
- Thus, we can find the force acting on the proton as,

Thus, we can conclude that the Lorentz force acting on the proton will be 3.15×10^-13 N.
Learn more about the Lorentz magnetic force here:
brainly.com/question/28047923
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60 minutes = 1h
500/x = 10/100
She swam 5 kilometers per hour.
a simple lifting machine consisting of a rope which unwinds from a wheel on to a cylindrical drum or shaft joined to the wheel to provide mechanical advantage. reeeeeeeeeeeeeeeeeeeeeeeeee
Answer
given,
y(x,t)= 2.20 mm cos[( 7.02 rad/m )x+( 743 rad/s )t]
length of the rope = 1.33 m
mass of the rope = 3.31 g
comparing the given equation from the general wave equation
y(x,t)= A cos[k x+ω t]
A is amplitude
now on comparing
a) Amplitude = 2.20 mm
b) frequency =


f = 118.25 Hz
c) wavelength




d) speed


v = 105.84 m/s
e) direction of the motion will be in negative x-direction
f) tension


T = 27.87 N
g) Power transmitted by the wave


P = 0.438 W
Explanation:
well there is nothing there and it could be different by diffrent objects, idk