Ask question

Ask question

All categories

IrinaVladis [17]

3 years ago

15

what 2 numbers should be placed in the blanks below so that the difference between consecutive numbers is the same? 17,_,_

,41

1 answer:

Komok [63]3 years ago

5 0

The answer is 25, 33. The difference between each consecutive number is 8.

You might be interested in

There are three balls for 40 cents or six balls for 60 cents. What percent dose he save by buying one set of six ball instead of

dsp73

Answer:

The persons saves 25% by buying one set of six ball instead of two sets of three balls.

Step-by-step explanation:

Cost of 1 set of three balls = 40 cents

Cost of 2 sets of three balls = 40 cents × 2 = 80 cents

Cost of 1 set of six balls = 60 cents

Percent dose he save by buying one set of six ball instead of two sets of three balls :

= $\frac{80 cents-60 cents}{80 cents}\times 100=25\%$

The persons saves 25% by buying one set of six ball instead of two sets of three balls.

3 0

3 years ago

Three men are trying to hold a ferocious lion still for the veterinarian. The lion, in the center,is wearing a collar with three

Andre45 [30]

The answer
<span>the third rope to counterbalance Sam and Charlie is F
and vectF +vectF1 +vectF2 =vect0
let's consider axis
y'y </span>vectF = -F
vectF 1= F1cos60
vectF 2= F2cos45
-F = -F1cos60-F2co45
so F= F1cos60+F2co45= 350x0.5+400x0.7=457.84 pounds

4 0

3 years ago

Thereisalinethatincludesthepoint(1, -10)andhasaslopeof

Paladinen [302]

Answer:

i dont know i am so sorry

Step-by-step explanation:

good luck with it though

3 0

3 years ago

Ten cars were recently assembled at a factory. Of these

bogdanovich [222]

Answer:

1/12

Step-by-step explanation:

5 0

1 year ago

Which of the values shown are potential roots of f(x) = 3x3 – 13x2 – 3x + 45? Select all that apply.

galina1969 [7]

Answer:

All potential roots are 3,3 and $-\frac{5}{3}$ .

Step-by-step explanation:

Potential roots of the polynomial is all possible roots of f(x).

$f(x)=3x^3-13x^2-3x+45$

Using rational root theorem test. We will find all the possible or potential roots of the polynomial.

p=All the positive/negative factors of 45

q=All the positive/negative factors of 3

$p=\pm 1,\pm 3,\pm 5\pm \pm 9,\pm 15\pm 45$

$q=\pm 1,\pm 3$

All possible roots

$\frac{p}{q}=\pm 1,\pm 3,\pm 5\pm \pm 9,\pm 15\pm 45,\pm \frac{1}{3},\pm \frac{5}{3}$

Now we check each rational root and see which are possible roots for given function.

$f(1)= 3\times 1^3-13\times 1^2-3\times 1+45\Rightarrow 32\neq 0$

$f(-1)= 3\times (-1)^3-13\times (-1)^2-3\times (-1)+45\Rightarrow \neq 32$

$f(-3)= 3\times (-3)^3-13\times (-3)^2-3\times (-3)+45\Rightarrow \neq -144$

$f(3)= 3\times (3)^3-13\times (3)^2-3\times (3)+45\Rightarrow =0\\\\ \therefore x=3\text{ Potential roots of function}$

Similarly, we will check for all value of p/q and we get

$f(-5/3)=0$

Thus, All potential roots are 3,3 and $-\frac{5}{3}$ .

5 0

2 years ago

Read 2 more answers