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Novay_Z [31]
4 years ago
6

You do a physics lab experiment on another planet. A small block is released from rest at the top of a long frictionless ramp th

at is inclined at an angle of 36.9° above the horizontal. You measure that a small block travels a distance 18.0 m down the incline in 5.70 s. What is the value of g, the acceleration due to gravity on this planet?
Physics
1 answer:
Alex Ar [27]4 years ago
5 0

Answer:

g= 1.8 m/s²

Explanation:

From conservation of energy we know:

mgh=\frac{1}{2}mv^2

Solving for g with h being the height of the ramp with angle ∅ and length L:

(1) g=\frac{v^2}{2h}=\frac{v^2}{2Lsin\theta}

The velocity v at the bottom of the ramp for a constant acceleration a in a time t is given by:

(2)v=at=gsin\theta t

Plugging equation 2 in to equation 1:

(3) g=\frac{2L}{sin\theta t^2}

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Answer:

The  value is  n  =  2.347 *10^{17} \  photons

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From the question we are told that

     The  amount of power delivered is  P  =  4.20 \  M W  =  4.20  *10^{6} \  W

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     E  =  P  * t  =  \frac{n  *  h  *  c  }{\lambda }

Where  h is the Planck's constant with value  h  =  6.262  *10^{-34} \  J \cdot  s

           c  is the speed of light with value  c =  3.0*10^{8} \  m/s

     

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    4.20 *10^{6}  *  16*10^{-9}=  \frac{n  *  6.626 *10^{-34}  *  3.0*10^{8}  }{694.3 *10^{-9}}

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