Explanation:
SUPONIENDO QUE LA ACELERACIÓN DE LA GRAVEDAD ES 
USANDO LA SEGUNDA LEY DE NEWTON:
<em>m</em> = 80.0 N/
= 8.16 kg
Answer:
Explanation:
This is the case of forced oscillation . The pendulum having the same or matching time period or angular frequency with that of angular frequency of external periodic force , will be in resonance having largest amplitude.
Angular frequency of pendulum having length .9 m
= 
l = .9
angular frequency
= 
= 3.33 rad / s
If we calculate angular frequencies of pendulum of all lengths given , we will find that other lengths do not give angular frequency falling between 2 and 4 radian . So only pendulum having length of .9 m will have vibration of maximum amplitude.
Answer:
(a) 498.4 Hz
(b) 442 Hz
Solution:
As per the question:
Length of the wire, L = 1.80 m
Weight of the bar, W = 531 N
The position of the copper wire from the left to the right hand end, x = 0.40 m
Length of each wire, l = 0.600 m
Radius of the circular cross-section, R = 0.250 mm = 
Now,
Applying the equilibrium condition at the left end for torque:



The weight of the wire balances the tension in both the wires collectively:



Now,
The fundamental frequency is given by:

where

(a) For the fundamental frequency of Aluminium:


where


(b) For the fundamental frequency of Copper:


where


Answer:
123.2 m/s after 28s
Explanation:
Vi= 0 m/s
a= 4.4 m/s^2
t=28s
Vf after 28s
To find Vf use your kinematics formula Vf=Vi+at
Vi is Zero so it gets removed and the equation becomes
Vf=at
Simply Plug and Solve
Vf= 4.4(28)
Vf=123.2 m/s after 28s