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Allushta [10]
3 years ago
15

What is 21,079,000.29 rounded to the nearest hundred thousand

Mathematics
2 answers:
forsale [732]3 years ago
8 0

21,100,000

Because the digit in the ten thousands place is greater than 5, you round the 0 in the hundred thousands place up to 1

Ymorist [56]3 years ago
3 0
The answer would be 21,000,000.00
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NEED HELP !!!!!
choli [55]
<span>61 pie  (please spell this "pi," not "pie.")  pi is irrational, so 61 pi is also irrational.

42  R

75.671523    If the fraction stops here (i. e., does not repeat), then this is R.

101      same as 101/1.  R
6/5       this is the ratio of 2 integers.  R</span>
6 0
3 years ago
At a sand and gravel plant, sand is falling off a conveyor and onto a conical pile at a rate of 16 cubic feet per minute. The di
kogti [31]

The rate at which the height of the pile is changing when the height is 2 ft. is 0.5659 ft./min. Computed using differentiation.

The sand is falling onto a conical pile, thus we get the pile in the shape of a cone, whose volume is given as:

<u>V = (1/3)πr²h</u>,

where V represents the volume of the cone, r represents its radius, and h represents its height.

In the question, we are given that the rate of piling is 16 ft.³/min, which implies that:

dV/dt = 16 ... (i)

We are also given that the diameter is three times the altitude (height), which can be shown as:

2r = 3h,

or, r  = (3/2)h.

Thus, the volume can now be shown as:

V = (1/3)π{(3/2)h}²h,

or, V = (3πh³)/4.

Differentiating this with respect to time, we get:

dV/dt = (3π/4)(3h²)dh/dt.

Now, we need to calculate the rate of change of height, when the height is  2 feet, thus we take h = 2

Using dV/dt = 16 from (i), we can write:

16 = (3π/4)(3(2)²)dh/dt.,

or, 16 = 9π(dh/dt),

or, dh/dt = 16/9π = 0.5659 ft./min.

Thus, the rate at which the height of the pile is changing when the height is 2 ft. is 0.5659 ft./min.

Learn more about differentiation at

brainly.com/question/13461339

#SPJ4

6 0
2 years ago
Plz help me with this
Finger [1]

Answer:    c) x = 5

<u>Step-by-step explanation:</u>

2\ log_3\ (x+4)-log_3\ 9=2\\\\2\ log_3\ (x+4)-log_3\ 3^2=2\\\\2\ log_3\ (x+4)-2=2\\\\2\ log_3\ (x+4)=4\\\\log_3\ (x+4)=2\\\\x + 4 = 3^2\\\\x+4=9\\\\\large\boxed{x=5}

3 0
3 years ago
Help.............???!!!
Studentka2010 [4]

Answer:

Its either A or C

Step-by-step explanation:

5 0
2 years ago
Look at the picture on top 63 points
Anton [14]

Answer:

how can we do that?

7 0
2 years ago
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