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3 years ago

10

Which table represents a function

1 answer:

solong [7]3 years ago

4 0

Answer:

The last one

Step-by-step explanation:

A function is where every x has only one y value.

You might be interested in

Which<br>expression is equivalent to 1/5m -20

muminat

There are infinite equivalent expressions. Here are some:

1/5(m-100)

20(1/100m-1)

1/5m-(4•5)

If you expand any of these or any of the terms, you will get an equivalent expression.

7 0

3 years ago

Arada [10]

Answer:

Gerrard

Step-by-step explanation:

Let the size of each poster be $x$

Eve's poster portion painted will be

$=\frac{1}{6}\times x\\=\frac{x}6}$

Gerrard's painted portion will be:

$=\frac{1}{5}\times x\\=\frac{x}{5}$

From the two inequalities, we find that $\frac{x}{5}$ is greater than $\frac{x}{6}$ by x/30

$\frac{x}{5}-\frac{x}{6}\\=\frac{x}{30}\\$

hence Gerrard has the larger blue section. His portion is 16.67% greater than Eve's

6 0

3 years ago

DESPERATELY NEED HELP ON THIS QUESTION

Triss [41]

Angle aed has to be 80 since the two triangles share two of the same angles

5 0

3 years ago

Find the value of X.

levacccp [35]

Answer:

52

Step-by-step explanation:

180 - 127 = 53

53 + 75 = 128

180 - 128 = 52

7 0

1 year ago

Initially 100 milligrams of a radioactive substance was present. After 6 hours the mass had decreased by 3%. If the rate of deca

Hitman42 [59]

Answer:

The half-life of the radioactive substance is 135.9 hours.

Step-by-step explanation:

The rate of decay is proportional to the amount of the substance present at time t

This means that the amount of the substance can be modeled by the following differential equation:

$\frac{dQ}{dt} = -rt$

Which has the following solution:

$Q(t) = Q(0)e^{-rt}$

In which Q(t) is the amount after t hours, Q(0) is the initial amount and r is the decay rate.

After 6 hours the mass had decreased by 3%.

This means that $Q(6) = (1-0.03)Q(0) = 0.97Q(0)$ . We use this to find r.

$Q(t) = Q(0)e^{-rt}$

$0.97Q(0) = Q(0)e^{-6r}$

$e^{-6r} = 0.97$

$\ln{e^{-6r}} = \ln{0.97}$

$-6r = \ln{0.97}$

$r = -\frac{\ln{0.97}}{6}$

$r = 0.0051$

So

$Q(t) = Q(0)e^{-0.0051t}$

Determine the half-life of the radioactive substance.

This is t for which Q(t) = 0.5Q(0). So

$Q(t) = Q(0)e^{-0.0051t}$

$0.5Q(0) = Q(0)e^{-0.0051t}$

$e^{-0.0051t} = 0.5$

$\ln{e^{-0.0051t}} = \ln{0.5}$

$-0.0051t = \ln{0.5}$

$t = -\frac{\ln{0.5}}{0.0051}$

$t = 135.9$

The half-life of the radioactive substance is 135.9 hours.

6 0

3 years ago