The number in the ones place= X
The number in the tenths place= y
y+x=14.
y=14-x
Original placement of numbers=10y+x
New placement of numbers(after subtraction of 36)= 10x+y
10y+ x-36=10x+y
Substitute y with 14-x
So we would get
10(14-x)+ x-36=10x+(14-x)
=140-10x+x-36=10x+14-x
After transposing we get
140-14-36=10x-x+10x-x
=90=18x
X=90/18
x=5
Y=14-x
=14-5
=9
So the two digit number is
10y+x
=90+5
=95
X y
-2 -3
-1 -1
0 1
1 3
2 5
i can’t graph it, but i hope this helps
I believe the correct answer from the choices listed above is option B. The solution to a system of inequalities is <span>a collection of points that satisfy all inequalities in the system. It will always be a number of points that will agree with the inequality.</span>
Hope this answers the question. Have a nice day.
1 = 1, 2, 3, 4, 5
4= 4, 8, 12, 16, 20
5= 5, 10, 15, 20, 25
