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Zielflug [23.3K]
4 years ago
10

Two people, that are 10.4 m apart, stretch a rope (2.31 kg) with a tension of 74.4 N. If one person sends a pulse through the ro

pe, how long will it take for the resulting disturbance to reach the other end? A. 0.5 sec B.0.585 sec C.0.54 sec D.0.568 sec
Physics
1 answer:
tresset_1 [31]4 years ago
3 0

Answer:

Option D. 0.568 s

Given:

Length of the rope, l = 10.4 m

mass of the rope, M = 2.31 kg

Tension, T = 74.4 N

Solution:

The velocity of the wave, v_{w} is given as:

v_{w} = \sqrt(\frac{T}{\frac{M}{l}})

Putting the values in the above formula:

v_{w} = \sqrt(\frac{74.4}{\frac{2.31}{10.4}})

v_{w} = \sqrt 334.96 = 18.30 m/s

Time taken, t can be calculated as:

t = \frac{distance}{speed or velocity}

Since distance between two end is the length of the rope

Therefore, using the formula for time, t:

t = \frac{10.4}{18.30}

t = 0.568 s

therefore, time taken for the disturbance to travel from one end to the other is t = 0.568 s

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A cat falls from a tree (with zero initial velocity) at time t = 0. How far does the cat fall between t = 1/2 and t = 1 s? Use Galileo's formula v(t) = −9.8t m/s.

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