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Alex Ar [27]
3 years ago
11

In Physics lab, Ellen has been given the task of constructing a simple motor. She must find common household items at home and b

ring them to class the following day. Her list of items include:
9 volt battery and leads, copper wire rotor, platform to hold the rotor, a magnet, and a wood base

She sets up her motor in physics lab the next day and finds that it works well. Which statement below explains the flow of energy through Ellen's motor?
A) battery-->electrical current-->copper wire rotor -->magnet--> mechanical energy
B) battery--> magnet--> electrical current--> copper wire rotor--> mechanical energy
C) magnet--> mechanical energy--> copper wire rotor--> battery--> electrical current
D) magnet--> copper wire rotor--> mechanical energy--> battery--> electrical current
Physics
2 answers:
Aleks [24]3 years ago
6 0

Answer:

a) battery-->electrical current-->copper wire rotor -->magnet--> mechanical energy

Explanation:

kiruha [24]3 years ago
4 0

Answer:

The answer is A.

Explanation:

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Marina86 [1]

Answer:

Skin

Explanation:

6 0
3 years ago
A current of 1.8 A delivers 2.5 C of charge. How much time was required? 0.70 s 0.72 s 1.4 s 4.5 s
Natalka [10]

Answer:

1.4 s

Explanation:

Given the following data;

Quantity of charge, Q = 2.5 C

Current = 1.8 A

To find the time required;

Mathematically, the quantity of charge passing through a conductor is given by the formula;

Quantity of charge, Q = current * time

Substituting into the formula, we have;

2.5 = 1.8 * time

Time = 2.5/1.8

Time = 1.4 s

5 0
3 years ago
Read 2 more answers
An unknown charged particle passes without deflection throughcrossed electric and magnetic fields of strengths 187,500 V/m and0.
UNO [17]

Explanation:

The given data is as follows.

        Electric field strength (E) = 187,500 V/m

    Magnetic field strength (B) = 0.125 T

       Diameter (d) = 25.05 cm = 0.2505 m    (as 1 m = 100 cm)

    Radius (r) = \frac{d}{2}

                    = \frac{0.2505}{2}

                    = 0.12525 m

Formula to calculate the magnetic force (F_{M}) is as follows.

              F_{M} = Bqv ............ (1)

Electrical force is calculated as follows.

             F_{E} = qE ............ (2)

On both electric and magnetic fields the velocity is perpendicular.

       F_{M} - F_{E} = 0

or,             F_{M} = F_{E}

Hence, from equations (1) and (2)

              Bqv = qE

or,            v = \frac{E}{B} ............. (3)

                  = \frac{187500 V/m}{0.125 T}

                  = 1,500,000 m/s

As the particle is moving in a semi-circular trajectory and motion of charged particle is given by the electric field as follows.

              F_{c} = \frac{mv^{2}}{r} ........... (4)

where,    F_{c} = centripetal force

             F_{M} = F_{c}

Using equation (1) and (4) as follows.

            F_{M} = F_{c}

              Bqv = \frac{mv^{2}}{r}

                   \frac{q}{m} = \frac{v}{Br}

                       = \frac{15 \times 10^{5}}{0.125 \times 0.12525}

                       = 958.08 \times 10^{5} C/kg

Thus, we can conclude that charge-to-mass ratio of the given particle is 958.08 \times 10^{5} C/kg.

8 0
3 years ago
A football wide receiver runs out from the line of scrimmage, turns around and runs 2 meters back toward the quarterback. Compar
nexus9112 [7]

Answer:

See below

Explanation:

TOTAL distance = x meters   (not given how far he ran from scrimmage line)

Displacement =  x - 2   meters     ( although football uses yards not meters)

3 0
2 years ago
Soil can best be described as the
mr Goodwill [35]
C. It is C because it really is loose covering.
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3 years ago
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