1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Kruka [31]
3 years ago
15

What is a tsunami? How is it formed?

Physics
2 answers:
IrinaK [193]3 years ago
4 0

A tsunami is a series of waves generated in an ocean or other body of water by a disturbance such as an earthquake, landslide, volcanic eruption, or meteorite impact. ... Undersea earthquakes, which typically occur at boundaries between Earth's tectonic plates, cause the water above to be moved up or down
PtichkaEL [24]3 years ago
4 0

<u>Answers:</u>


1. A tsunami, also known as a <u>seaquake</u> is a seism whose epicenter is located at the depths of the sea or ocean (or any a mass of water) producing the agitation of the waters and forming large waves.

2. How is it formed?

After the seism at the depth of the mass of water begins, and if the seism has a <u>vertical component</u>, the movement causes a displacement of the sea bottom and, consequently, it causes the formation giant waves as the water is displaced because of gravity, trying to return to a stable position.

Now, when the tsunami approaches the coast its <u>speed decreases</u>, because <u>the depth decreases</u>, in other words, the water accumulates when braking, <u>increasing the height of the wave</u>.


And, according to the <u>conservation of energy</u> principle, if the speed of the wave decreases, its height increases.



You might be interested in
f the magnitude of the acceleration of a propeller blade's tip exceeds a certain value amaxamax, the blade tip will fracture. If
Luden [163]

Answer:

The angular velocity is   w= \sqrt[4]{\frac{a_{max}^2}{r^2}  - \alpha ^2}      

Explanation:

Generally the acceleration experienced by the propeller blade's is broken down into

          The Radial acceleration which is mathematically represented as

                              a_r = \frac{v^2}{r}  = w^2r

And the Tangential  acceleration which is mathematically represented as

                                a_r = \alpha r

  The net acceleration is evaluated as

                      a = \sqrt{a_r^2 + a_t^2}

       

Now since angular speed varies directly with angular acceleration so when acceleration is maximum the angular velocity is maximum also and this point if the propeller blade's tip exceeds it the blade would fracture

                 

So at maximum angular acceleration we a have

             a_{max} = \sqrt{a_r^2 + a_t^2}

                     a_{max}^2 = a_r^2 + a_t^2

                    a_{max}^2 = (w^2r)^2 + (\alpha r)^2

                 a_{max}^2 =  r^2 w^4 + r^2 \alpha ^2

                  a_{max}^2 = r^2 (w^4 + \alpha^2 )

                w^4 +\alpha ^2 = \frac{a_{max}^2}{r^2}

                         w^4 = \frac{a_{max}^2}{r^2}  - \alpha ^2

                         w= \sqrt[4]{\frac{a_{max}^2}{r^2}  - \alpha ^2}        

                     

3 0
3 years ago
In a Rutherford scattering experiment a target nucleus has a diameter of 1.34×10-14 m. The incoming α particle has a mass of 6.6
Rasek [7]

Answer:

E = 2.5 x 10⁻¹⁴ J

Explanation:

given,

diameter = 1.33 x 10⁻¹⁴ m

mass = 6.64 x 10⁻²⁷ kg

wavelength is equal to diameter

de broglie wavelength equal to diameter

         \lambda = \dfrac{h}{mv}

         1.33 \times 10^{-14}= \dfrac{6.626 \times 10^{-34}}{6.64 \times 10^{-27}\times v}

         v= \dfrac{6.626 \times 10^{-34}}{6.64 \times 10^{-27}\times 1.33 \times 10^{-14}}

              v = 7.5 x 10⁶ m/s

Kinetic energy is equal to

     E = \dfrac{1}{2}mv^2

     E = \dfrac{1}{2}\times 6.64 \times 10^{-27}\times (7.5\times 10^6)^2

            E = 2.5 x 10⁻¹⁴ J

8 0
3 years ago
a car goes from a velocity zero to a velocity of 15 meters per second East in 2.1 seconds. What is the car's acceleration?
leva [86]
31.5 would be the acceleration.
3 0
3 years ago
Anna drew a diagram to compare the strong and weak force. Which labels belong in the areas marked X, Y, and Z? X: infinite range
Maslowich

Answer:

For areas marked X, Y, Z, X is attractive only, Y has a very small range, and Z is attractive and repulsive

Explanation:

Solution

Given that:

From the question stated, Anna drew a diagram to compare forces that are strong and weak.

Now,

We are to find which labels are grouped in areas marked as X, Y, Z respectively.

Thus,

For X, Y, Z it is marked as:

X: Always attractive  or attractive only

Y: Very small range

Z:  Repulsive and attractive

8 0
3 years ago
True or False: The arrows on a motion map should point in the directions of motion.
slavikrds [6]

Answer:

true,true,false

Explanation:

its false because if it is equal it would show an arrow pointing left and a 20 and the same for the right

3 0
3 years ago
Other questions:
  • Can some help me out on some science ?
    5·2 answers
  • If block D weighs 300 lb and block B weighs 275 lb determine the required weight of block C and the angle theta for equilibrium?
    10·1 answer
  • How are sound waves different from light (and other electromagnetic, waves?
    11·1 answer
  • If a child ran into the road 65 to 70 feet ahead of your vehicle, what is the highest speed from which you could stop with good
    12·1 answer
  • 1.
    11·2 answers
  • In which of the following situations would be the government had been most likely to become involved in union protests?
    6·1 answer
  • Points of maximum amplitude on a standing wave are called
    15·1 answer
  • What happens to the speed of an object that is dropped in free fall
    13·1 answer
  • Which of the following occurs during the evolution of a star?
    15·1 answer
  • Did you diagram all the faults and folds correctly? Which fault and/or fold did you find most difficult to diagram?
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!