Answer:
The car's displacement during this time is 25.65 meters.
Explanation:
Given that,
Final velocity of the car, v = 4.5 m/s
Deceleration of the car, 
Let u is the initial speed of the car. It is given by :
u = 12.6 m/s
Let d is the car's displacement during this time. It can be calculated using second equation of motion as :
d = 25.65 meters
So, the car's displacement during this time is 25.65 meters. Hence, this is the required solution.
Answer:
0.017 N
Explanation:
The relevant relation is ...
F = GMm/r²
where G is the universal gravitational constant, 6.67408 × 10^-11 m^3·kg^-1·s^-2, M and m are the masses of the objects, and r is the distance between them.
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Filling in the given numbers, we find the force to be ...
F = (6.67408 × 10^-11 m^3·kg^-1·s^-2)(8.7 × 10^20 kg)(77 kg)/(1.6 × 10^7 m)^2
where m in this expression is the unit "meters".
F = 6.67408 · 8.7 · 77/2.56 × 10^(-11 +20 -2·7) N ≈ 0.017 N
The asteroid exerts a force of about 0.017 N on Sally.
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<em>Additional comment</em>
That's about 0.000023 times the force of Earth's gravity.
A wave with a greater amplitude carries more energy to wherever it goes.
Answer:
350 miles
Explanation:
When the car starts 2 hours later, the train would have a head start of
50 * 2 = 100 miles
The speed of the car relative to the train is
70 - 50 = 20 mi/hr
For the car to catch up with the train, it must cover the 100 miles difference at the rate of 20mi/hr. So the time it would need to cover this difference is
100 / 20 = 5 hours
After 5 hours, the car would have traveled a distance of
5 * 70 = 350 miles which is also the distance from the station to where the car catches up
Answer:
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Explanation:
