According to the New Jersey Driver Manual, if a driver has a blood alcohol concentration (BAC) of 0.15%, he or she is ____ times
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Answer: In this type of cross between MmDdPp and mmddpp, the phenotypic ratios in the eight possible phenotypes are as follow; a. solid, normal, smooth = 1:8
b. solid, normal, peach = 1:8
c. solid, dwarf, smooth = 1:8
d. solid, dwarf, peach = 1:8
e. mottled, normal, smooth = 1:8
f. mottled, normal, peach = 1:8
g. mottled, dwarf, smooth = 1:8
h. mottled, dwarf, peach = 1:8
Explanation: The number of gametes that can be formed from a particular genotype is given as 2^n where n is the number of heterozygous loci. In the genotype MmDdPp, n = 3. Therefore, 8 gametes can be formed.
In genotype mmddpp, n = 0. Therefore, only one type of gamete can be formed.
Crossing the two genotype (MmDdPp and mmddpp) as shown in the attached image, 8 possible offsprings can be achieved. Phenotypes of these offspring had been stated earlier. The phenotypic frequency of each of these offspring is one out of eight (⅛).
Parents: Homozygous brown-eyed (M) - B B
blued-eye (F) - b b [since blue (b) is recessive then and brown (B) is dominant then
in order for the blue gene to
show the you need double recessive or the brown
gene absent
Offspring:
So based on the Punnett cross then you realize that all the possible of spring carry the genotype B b and as such the phenotype brown eyes
blued-eye (F) - b b [since blue (b) is recessive then and brown (B) is dominant then
in order for the blue gene to
show the you need double recessive or the brown
gene absent
Offspring:
So based on the Punnett cross then you realize that all the possible of spring carry the genotype B b and as such the phenotype brown eyes