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2 years ago

3^x ( x^2 -3) i don't know how to solve this problem

1 answer:

7 0

3ˣ (x² - 3)

Basically, just multiply everything together.

Step 1 : 3x × x² = 3x³ because when multiplying exponents, all you're really doing is adding them on top. So, x + 2x = 3x! But, they are exponents, so you get 3x³.

Step 2 : 3x ˣ × (-3) = -9ˣ

Now, our new question is : 3x³ - 9x

You wouldn't simplify this because x³ is NOT the same as x.

~Hope I helped!~

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Vika [28.1K]

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2 years ago

A circle with radius \pink{6}6start color #ff00af, 6, end color #ff00af has a sector with a central angle of \purple{48^\circ}48

alexandr1967 [171]

Answer:

Therefore,

The area of the sector is 15.09 unit².

Step-by-step explanation:

Given:

Circle with,

radius = r = 6 unit

central angle = θ = 48°

pi = 3.143

To Find:

Area of sector = ?

Solution:

If 'θ' is in degree the area of sector is given as

$\textrm{Area of Sector}=\dfrac{\theta}{360}\times \pi r^{2}$

Substituting the values we get

$\textrm{Area of Sector}=\dfrac{48}{360}\times 3.143\times 6^{2}$

$\textrm{Area of Sector}=15.0864=15.09\ unit^{2}$ rounded to nearest hundredth

Therefore,

The area of the sector is 15.09 unit².

7 0

2 years ago

Read 2 more answers

There was no snow on the ground when it started falling at midnight at a constant rate of 1.5 inches per hour. At

kumpel [21]

Answer:

The required piece-wise linear function is

$\left\{\begin{matrix}1.5x & 0\leq x$

Step-by-step explanation:

Consider the provided information.

Let x represents the number of hours and S(x) represents the depth of snow.

There was no snow on the ground when it started falling at midnight at a constant rate of 1.5 inches per.

That means the depth of snow will be:

$S(x)=1.5x\ \ \ 0\leq x< 4$

At 4:00 a.m., it starting falling at a constant rate of 3 inches per hour,

From mid night to 4:00 a.m the depth of snow will be 1.5×4=6 inches.

If we want to calculate the total depth of snow from midnight to 7:00 am we need to add 6 inches in 3(x-4) where 4≤x<7

Therefore,

$S(x)=3(x-4)+6\ \ \ 4\leq x$

7:00 a.m. to 9:00 a.m., snow was falling at a constant rate of 2 inches per hour.

From mid night to 7:00 a.m the depth of snow will be 3(7-4)+6=15 inches.

If we want to calculate the total depth of snow from midnight to 9:00 am we need to add 15 inches in 2(x-7) where 7≤x≤9

$S(x)=2(x-7)+15\ \ \ 7\leq x\leq 9$

Therefore, the required piece-wise linear function is

$\left\{\begin{matrix}1.5x & 0\leq x$

8 0

2 years ago

Find the measure of the indicated arc

natali 33 [55]

Answer:

m $\widehat{WXY}$ is 224°

Step-by-step explanation:

From the figure, we have;

The angle subtended at the circumference, by the arc mWXY, C = 112°

The angle subtended at the center = m $\widehat{WXY}$

By circle theory, we have;

The angle subtended at the center = 2 × The angle subtended at the circumference

∴ m $\widehat{WXY}$ = 2 × 112° = 224°

m $\widehat{WXY}$ = 224°.

7 0

2 years ago

What are the restrictions for a? 2a^2+a-15/5a^2+16a+3

koban [17]

ANSWER

The restrictions are

$a\ne -3,a\ne -\frac{1}{5}$

EXPLANATION

We were given the rational function,

$\frac{2a^2+a-15}{5a^2+16a+3}$

The function is defined for all values of a, except

$5a^2+16a+3=0$

This has become a quadratic trinomial, so we need to split the middle term.

We do that by multiplying the coefficient of $x^2$ which is 5 by the constant term which is 3. This gives us 15.

The factors of 15 that adds up to 16 are 1 and 15.

We use these factors to split the middle term.

$5a^2+15a+a+3=0$

We now factor to get,

$5a(a+3)+1(a+3)=0$

We factor further to get,

$(a+3)(5a+1)=0$

This implies that,

$(a+3)=0,(5a+1)=0$

This gives

$a=-3,a=-\frac{1}{5}$

These are the restrictions.

8 0

3 years ago