<span>significant figures: 7, decimals: 3</span>
Answer:
2.99×10²⁵ molecules of CO₂ are produced
Explanation:
Decomposition reaction is:
Ca(HCO₃)₂ => CaO(s) + 2CO₂(g) + H₂O(g)
Ratio is 1:2. Let's make a rule of three:
1 mol of bicarbonate can produce 2 moles of CO₂
Therefore, 24.9 moles of bicarbonate may produce, 49.8 moles (24.9 .2 )/1
Let's determine the number of molecules
1 mol has 6.02×10²³ molecules
49.8 moles must have (49.8 . 6.02×10²³) / 1 = 2.99×10²⁵ molecules
Answer:
3966.82 J
Explanation:
q=sm∆T
q=73×13×4.18
the specific heat for water is 4.18
Answer:
d hope this helps u hhwjs GD jehehj
Volume of Hydrogen V1 = 351mL
Temperature T1 = 20 = 20 + 273 = 293 K
Temperature T2 = 38 = 38 + 273 = 311 K
We have V1 x T2 = V2 x T1
So V2 = (V1 x T2) / T1 = (351 x 311) / 293 = 372.56
Volume at 38 C = 373 ml
