Answer:
3.052 × 10^24 particles
Explanation:
To get the number of particles (nA) in a substance, we multiply the number of moles of the substance by Avogadro's number (6.02 × 10^23)
The mass of Li2O given in this question is as follows: 151grams.
To convert this mass value to moles, we use;
moles = mass/molar mass
Molar mass of Li2O = 6.9(2) + 16
= 13.8 + 16
= 29.8g/mol
Mole = 151/29.8g
mole = 5.07moles
number of particles (nA) of Li2O = 5.07 × 6.02 × 10^23
= 30.52 × 10^23
= 3.052 × 10^24 particles.
Tin metal reacts with hydrogen fluoride to produce tin(II) fluoride and hydrogen gas according to the following balanced equation.
Sn(s)+2HF(g)→SnF2(s)+H2(g)
Sn(s)+2HF(g)→
SnF
2
(s)+
H
2
(g)
How many moles of hydrogen fluoride are required to react completely with 75.0 g of tin?
Step 1: List the known quantities and plan the problem.
Known
given: 75.0 g Sn
molar mass of Sn = 118.69 g/mol
1 mol Sn = 2 mol HF (mole ratio)
Unknown
mol HF
Use the molar mass of Sn to convert the grams of Sn to moles. Then use the mole ratio to convert from mol Sn to mol HF. This will be done in a single two-step calculation.
g Sn → mol Sn → mol HF
Step 2: Solve.
75.0 g Sn×1 mol Sn118.69 g Sn×2 mol HF1 mol Sn=1.26 mol HF
75.0 g Sn×
1
mol Sn
118.69
g Sn
×
2
mol HF
1
mol Sn
=1.26 mol HF
Step 3: Think about your result.
The mass of tin is less than one mole, but the 1:2 ratio means that more than one mole of HF is required for the reaction. The answer has three significant figures because the given mass has three significant figures.
The answer is
2Ag+(aq) + SO4-2(aq) → Ag2SO4(s)
<span>NO3- and K+ ions are spectators </span>
Three uses of coal:
1. Electricity generation
2. Steel production
3. Cement manufacturing and as a liquid fuel
Hope it helps!
Answer:
The name of this compound is :
Bi2(CO3)3 = Bismuth Carbonate
Explanation:
The name of the compound is derived from the name of the elements present in it.
The rule followed while naming the compound are:
1. The first element (always the cation) is named as such .
2. The second element (The anion) end with "-ate , -ide ," etc
3. NO prefix is added while naming the first element.
For example : Bi2 can't be named as Dibismuth
Na2 = Can't be named as disodium
Hence the compound :
Bi2(CO3)3 contain two element : Bi and CO3. Here , Bi = cation (named as such) and CO3 = anion (named according to rules)
Bi = Bismuth
CO3 = carbonate
Bi2(CO3)3 = Bismuth Carbonate
The molecular mass of this compound is :
Molecular mass = 2 (mass of Bi) + 3(mass of C) + 6(mass of O)
= 2 (208.98)+3(12.01)+6(15.99)
= 597.987 u
