The answer is D. Distilling.
Answer:
162g
Explanation:
We'll begin by writing the balanced equation for the reaction. This is given below:
2C2H6 + 7O2 —> 4CO2 + 6H2O
Next, we shall determine the number of mole of water, H2O produced by the reaction of 3 moles of C2H6.
This can be obtained as follow:
From the balanced equation above,
2 moles of C2H6 reacted to produce 6 moles of H2O.
Therefore, 3 moles of C2H6 will react to produce = (3 x 6)/2 = 9 moles of H2O.
Therefore, 9 moles of H2O is produced from the reaction.
Finally, we shall convert 9 moles of H2O to grams.
This can be done as shown below:
Molar mass of H2O = (2x1) + 16 = 18g/mol
Mole of H2O = 9 moles
Mass of H2O =..?
Mole = mass / molar mass
9 = mass of H2O /18
Cross multiply
Mass of H2O = 9 x 18
Mass of H2O = 162g
Therefore, 162g of H2O were produced from 3 moles of C2H6.
Answer:
Explanation:
Trick question. The cathode is where the reduction reaction takes place. The reduction reaction is the gain of electrons.
Pb+2 + 2e^- ===> Pb The eo for that is - 0.126.
The minus sign indicates that the Pb^2+ is not overjoyed at taking on those two electrons. If it had a say in the matter, it would rather be giving up electrons. In other words, it would rather be the oxidizing equation which would look like this
Pb ===> Pb+2 + 2e^- and the oxidizing potential would be eo = + 0.126
That's what moving right and moving left means. If the eo is - then the preferred reaction is the opposite one.
This is a real language problem and if Znk answers you can take his answer to the bank.
Answer:
0.056 M
Explanation:
To calculate the concentration of h we must use the following formula:
10^-pH
So lets plug in our pH:
10⁻¹.²⁵
When we plug this into our calculator our answer is
0.056 M
The solubility is the guide to the maximum amount of solute that can be dissolved in a certain amount of solvent at a certain temperature to make a saturated solution. Any amount less than this would result to unsaturated, while any amount more would result to saturated.
6 g/(50 mL * 1 L/1000 mL) = 120 g/L
Since it is less than the solubility of 125 g/L, then <em>this solution is unsaturated</em>.
