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tensa zangetsu [6.8K]
3 years ago
9

Which statements describe a closed circuit? Check all that apply.

Chemistry
2 answers:
Verdich [7]3 years ago
8 0

The answer is:

"Bulbs will shine.

The circuit is complete.

Charges flow."

I just took the test and got it right, good luck!

ehidna [41]3 years ago
7 0

Answer:

The answers are options A, D and E

Explanation:

Shut circuit implies a total electrical association around which flow streams or courses. When you have a progression of electrical wires interfacing with one another and finishing a circuit so flow goes from one end of the hover to alternate, this is a case of a shut circuit. A broken wire or an "open" (off) switch both leave holes in a circuit keeping electrons from going from one side of the power source to the next. In this way, electrons won't stream. This circumstance is called an open circuit. A shut (on) switch implies that the circuit through the switch is connected.The meaning of an open circuit is a broken way for an electrical flow because of an open switch or frayed wire. A case of an open circuit is a string of electric lights that don't work on the off chance that one globule goes out. YourDictionary definition and utilization precedent. Shut circuit implies an entire electrical association around which flow streams or circles. When you have a progression of electrical wires associating with one another and finishing a circuit so flow goes from one end of the hover to alternate, this is a case of a shut circuit.

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rosijanka [135]

Answer:hypothesis

Explanation:

4 0
3 years ago
Based on the sign of E cell, classify these reactions as spontaneous or non spontaneous as written.? assume standard conditions.
sammy [17]
A electrochemical reaction is said to be spontaneous, if E^{0} cell is positive. 

Answer 1:
Consider reaction: <span>Ni^2+ (aq) + S^2- (aq) ----> + Ni (s) + S (s) 

The cell representation of above reaction is given by;
    </span>S^{2-}/S //  Ni^{2+}/Ni

Hence, E^{0}cell =  E^{0} Ni^{2+/Ni} -  E^{0} S/S^{2-}
we know that, {E^{0} Ni^{2+}/Ni  = -0.25 v
and {E^{0} S/ S^{2-}  = -0.47 v

Therefore, E^{0} cell = - 0.25 - (-0.47) = 0.22 v

Since,  E^{0} cell is positive, hence cell reaction is spontaneous
.....................................................................................................................

Answer 2: 
Consider reaction: <span>Pb^2+ (aq) +H2 (g) ----> Pb (s) +2H^+ (aq)
</span>
The cell representation of above reaction is given by;
    H_{2} /  H^{+} //  Pb^{2+} /Pb

Hence, E^{0}cell = E^{0} Pb/Pb^{2+} - E^{0} H_{2}/H^{+}
we know that, {E^{0} Pb^{2+}/Pb = -0.126 v
and {E^{0} H_{2}/ H^{+} = -0 v

Therefore, E^{0} cell = - 0.126 - 0 = -0.126 v

Since,  E^{0} cell is negative, hence cell reaction is non-spontaneous.

....................................................................................................................

Answer 3: 
Consider reaction: <span>2Ag^+ (aq) + Cr(s) ---> 2 Ag (s) +Cr^2+ (aq)
</span>
The cell representation of above reaction is given by;
    Cr/Cr^{2+} // Ag^{+}/Ag

Hence, E^{0}cell = E^{0} Ag^{+}/Ag - E^{0} Cr/Cr^{2+}
we know that, {E^{0} Ag^{+}/Ag = -0.22 v
and {E^{0} Cr/ Cr^{2+} = -0.913 v

Therefore, E^{0} cell = - 0.22 - (-0.913) = 0.693 v

Since,  E^{0} cell is positive, hence cell reaction is spontaneous
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4 years ago
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Answer:

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Explanation:

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Explanation:

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Answer:

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Explanation:

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