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frutty [35]
3 years ago
5

Which statement is true? Energy cannot be created or destroyed. Energy can be destroyed but not created. Energy can be created b

ut not destroyed.
Chemistry
2 answers:
vaieri [72.5K]3 years ago
6 0
Energy can not be created and cannot be destroyed
<span />
Kryger [21]3 years ago
5 0
Energy is neither created or destroyed, so your answer would be A. Energy is not created or destroyed. Hope this helps
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Arachidonic acid and pge1 are both carboxylic acids with atoms. the differences are that arachidonic acid contains and no other
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Answer:
             <span>Arachidonic Acid and PGE</span>₁<span> are both carboxylic acids with <u>Twenty Carbon</u> atoms. The differences are that Arachidonic acid contains <u>Four <em>cis</em> Double Bonds</u> and no other functional groups, whereas PGE</span>₁<span> has <u>One <em>Trans</em> Double Bond, Two Hydroxyl and One Ketone Functional Groups.</u>. In addition, a part of the PGE</span>₁<span> chain forms a <u>Five Membered Ring</u>.

Structures of Both Arachidonic Acid and PGE</span>₁ are shown Below,

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What properties are associated with metals (grade 9 science)
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metals can be magnetic.

Explanation:

certain types of metals are magnetic.

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What is the connection between physical properties and physical changes
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Explanation:

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How the government support communities affected by xenophobia​
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Write a net ionic equation for the overall reaction that occurs when aqueous solutions of sodium hydroxide and hydrosulfuric aci
Helga [31]

Answer:

2OH-(aq) + 2H+(aq) → 2H2O(l)

Explanation:

Step 1: Data given

sodium hydroxide = NaOH

hydrosulfuric acid = H2S

Step 2: The unbalanced equation

NaOH(aq) + H2S(aq) → Na2S(aq) + H2O(l)

Step 3: Balancing the equation

On the left side we have 1x Na (in NaOH), on the right side we have 2x Na (in Na2S). To balance the amount of Na on both sides, we have to multiply NaOH on the left side by 2.

2NaOH(aq) + H2S(aq) → Na2S(aq) + H2O(l)

On the left side we have 4x H (2x in NaOH and 2x in H2S), on the right side we have 2x H (in H2O). To balance the amount of H on both sides, we have to multiply H2O on the right side by 2. Now the equation is balanced.

2NaOH(aq) + H2S(aq) → Na2S(aq) + 2H2O(l)

Step 4: The net ionic equation

2Na+(aq) + 2OH-(aq) + 2H+(aq) + S^2-(aq) → 2Na+(aq) + S^2-(aq) + 2H2O(l)

The net ionic equation, for which spectator ions are omitted - remember that spectator ions are those ions located on both sides of the equation - will , after canceling those spectator ions in both side, look like this:

2OH-(aq) + 2H+(aq) → 2H2O(l)

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