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3 years ago

5

Which statement is true? Energy cannot be created or destroyed. Energy can be destroyed but not created. Energy can be created b

ut not destroyed.

2 answers:

vaieri [72.5K]3 years ago

6 0

Energy can not be created and cannot be destroyed
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Kryger [21]3 years ago

5 0

Energy is neither created or destroyed, so your answer would be A. Energy is not created or destroyed. Hope this helps

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Help me out please an thank you

ivanzaharov [21]

The second one, I could be mistaken though

3 0

3 years ago

The complementary base sequence to GTAGCT is:_______.A) CATCGA.B) ACGATC.C) GCAGTA.D) AGTCGA.E) None of the above

IceJOKER [234]

Answer:none of the above

Explanation:

8 0

3 years ago

In a calorimetry experiment, a salt is dissolved in water within an insulating container. The temperature of the solution (surro

Stels [109]

Answer:

Explanation:

heat released by the solution

= 120 x 3.18 x ( 25 - 14 )

= 4197.6 J

= 4.1976 kJ

This is the heat gain by the salt

so enthalpy change = + 4.1976 kJ

because there is increase in enthalpy

It is endothermic process .

7 0

3 years ago

Iron(III) oxide and hydrogen react to form iron and water, like this: Fe_2O_3(s) + 3H_2(g) rightarrow 2Fe(s) + 3H_2O(g) At a cer

Sergeeva-Olga [200]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The equilibrium constant is $K_c= 2.8*10^{-4}$

Explanation:

From the question we are told that

The chemical reaction equation is

$Fe_{2} O_{3}_{(s)} + 3H_{2}_{(g)} -----> 2Fe_{(s)} + 3H_{2} O_{(g)}$

The voume of the misture is $V_m = 5.4L$

The molar mass of $Fe_{2} O_{3}_{(s)}$ is a constant with value of $M_{Fe_{2} O_{3}_{(s)} } = 160g/mol$

The molar mass of $H_{2}_{(g)}$ is a constant with value of $H_2 = 2g/mol$

The molar mass of $H_{2}O$ is a constant with value of $H_2O = 18g/mol$

Generally the number of moles is mathematically given as

$No \ of \ moles \ = \frac{mass}{molar\ mass}$

For $Fe_{2} O_{3}_{(s)}$

$No \ of\ moles = \frac{3.54}{160}$

$= 0.022125 \ mols$

For $H_{2}$

$No \ of\ moles = \frac{3.63}{2}$

$= 1.815 \ mols$

For $H_{2}O$

$No \ of\ moles = \frac{2.13}{18}$

$= 0.12 \ mols$

Generally the concentration of a compound is mathematicallyrepresented as

$Concentration = \frac{No \ of \ moles }{Volume }$

For $Fe_{2} O_{3}_{(s)}$

$Concentration[Fe_2 O_3] = \frac{0.222125}{5.4}$

$= 4.10*10^{-3}M$

For $H_{2}$

$Concentration[H_2] = \frac{1.815}{5.4}$

$= 0.336M$

For $H_{2}O$

$Concentration [H_2O] = \frac{0.12}{5.4}$

$= 0.022M$

The equilibrium constant is mathematically represented as

$K_c = \frac{[concentration \ of \ product]}{[concentration \ of \ reactant ]}$

Considering $H_2O \ for \ product$

And $H_2 \ for \ reactant$

At equilibrium the

$K_c = \frac{0.022}{0.336}$

$K_c= 2.8*10^{-4}$

3 0

3 years ago

How many oxygen atoms are in 2(NO3)

torisob [31]

6 Oxygen atoms

Explanation:

In the molecule 2(NO₃):

An atom is the smallest indivisible particle of any substance. They chemically combine to give compounds and molecules. Some of them are able to exist on their own.

An element is a substance that has a unique atom.

NO₃ has two elements: N and O

Number of atoms:

N = 1

O = 3

but we have two moles of NO₃

O = 3 x 2 = 6

N = 1 x 2 = 2

learn more:

Number of atoms brainly.com/question/10419836

#learnwithBrainly

5 0

3 years ago