Given:
m(mass of the car)=1134 Kg
u(Initial velocity)=83Km/HR=23m/s
s(distance traveled by the car)=98m
v(final velocity)=0(as it is given the car stops).
Now we know,
v=u+at
Where v is the final velocity
u is the initial velocity
a is the acceleration
t is the time
0=23+at
at=-23
Also
s=ut+1/2(at^2)
s is the distance covered by the car
u is the initial velocity
t is the time necessary for the car to cover a particular distance.
a is the acceleration
Now substituting these values we get
98=23t-1/2(23t)
98=23t-11.5t
11.5t=98
t=8.52secs
Now we have already derived
at=-23
ax8.52=-23
a=-23/8.52
a=-2.75 m/s^2
F=mxa
Where F is the force acting on the car.
m is the mass of the car.
a is the acceleration.
F=1134 x-2.75
F=-3119N
Answer: Tom drove 60 km/hr fast
Speed = Distance traveled / time taken
Explanation:
Given that:
Distance traveled by Tom = 60 km
Time taken by Tom = 1 hour
Speed = ?
Since speed is obtained by dividing distance traveled by the time taken, hence the formula to use is as follows:
speed = distance / time
Speed = 60 km / 1 hour
Speed = 60 km/hr
Thus, Tom had been driving 60 km/hr fast, using the formula "speed = distance / time"
Answer:
19.53 cm
Explanation:
The computation of the height is as follows:
Here we applied the conservation of the energy formula
As we know that
P.E of the block = P.E of the spring
m g h = ( 1 ÷ 2) k x^2
where
m = 0.15
g = 9.81
k = 420
x = 0.037
So now put the values to the above formula
(0.15) (9.81) (h) = 1 ÷2 × 420 × (0.037)^2
1.4715 (h) = 0.28749
h = 0.19537 m
= 19.53 cm
Answer:
Direct current.
Explanation:
The electric current is defined as the electric charge flowing per unit time. There are two types of current i.e. direct current and alternating current. The unidirectional flow of current describes the direct current. It is said so because the direct current flows only in one direction. This type of current flows in semiconductors, insulators, conductors etc. It is also known as DC current.