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bekas [8.4K]
4 years ago
10

Ryan is experimenting with core materials for an electromagnet. He slides different core materials through a coil of current-car

rying wire. Sort the core materials based on whether they will or won’t increase the strength of Ryan’s electromagnet.
Physics
2 answers:
Fudgin [204]4 years ago
7 0

Answer:

We can say that electromagnet is coils of wire which behave like bar magnets with a distinct South and North poles when a current of electricity passes through the coil.

The bigger the strength of Ryan's electromagnet, the better the conductivity of the material.

The material is as follows,

1. Silver and it is the best conductor.

2. Iron.

3. Nickel

4. Steel.

5. Glass which is an insulator, and

6. wood which is an insulator, and we thoroughly know that insulators they don't conduct electricity.

Explanation:

Arte-miy333 [17]4 years ago
5 0
Will increase strength: iron, nickel, steel
won't increase strength: wood, silver, glass

^thats on Plato
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A periodic wave travels from one medium to another. Which pair of variables are likely to change in the process? A. velocity and
Lesechka [4]

Answer:

A. velocity and wavelength

Explanation:

When a wave travels from one medium to another it undergoes refraction which results to the change in direction.

Refraction of a wave is one of the property of waves that occurs when a wave changes direction when it passes from one medium to another. This occurs as a result of bending of the wave which occurs since the mediums involved are of different density and refractive index.

Apart from the change in direction, refraction is accompanied by the change in wavelength of a wave and thus a change in speed.

5 0
3 years ago
you push a 51 kg box with a force of 485 N. the friction force on the box is 232 N. calculate the acceleration of the crate.
vichka [17]

Answer:

a = 4.96 m/s²

Explanation:

Given,

The mass of the box, m = 51 Kg

The magnitude of the applied force, Fₐ = 485 N

The friction force on the box, Fₓ = 232 N

The net force acting on the box is,

                                 F = Fₐ - Fₓ

Substituting the given values in the above equation

                                  F = 485 - 232

                                    = 253 N

The acceleration of the crate is given by

                                   a = F/m

                                      = 253 / 51

                                      = 4.96 m/s²

Hence, the acceleration of the crate is, a = 4.96 m/s²

3 0
3 years ago
Help me please please help me
andreev551 [17]
Answers:

1. B. Circuit
2. D. Electrons moving around
3. B. Series and parallel
4. C. Parallel
5. C. Series
6. A. One
7. C. If one goes down, they both go down.

Hope this helped!
5 0
3 years ago
Which of the following statements best describes the method of energy conservation known as cogeneration?
Mazyrski [523]

Answer:

heat and power

Explanation:

is the simultaneous production of electricity and heat both of which are used

6 0
3 years ago
A motorcycle is following a car that is traveling at constant speed on a straight highway. Initially, the car and the motorcycle
xz_007 [3.2K]

Answer:

a) \Delta{t} = 5.39s

b) the motorcycle travels 155 m

Explanation:

Let t_2-t_1 = \Delta{t}, then consider the equation of motion for the motorcycle (accelerated) and for the car (non accelerated):

v_{m2}=v_0+a\Delta{t}\\x+d=(\frac{v_0+v_{m2}}{2} )\Delta{t}\\v_c = v_0 = \frac{x}{\Delta{t}}

where:

v_{m2} is the speed of the motorcycle at time 2

v_{c} is the velocity of the car (constant)

v_{0} is the velocity of the car and the motorcycle at time 1

d is the distance between the car and the motorcycle at time 1

x is the distance traveled by the car between time 1 and time 2

Solving the system of equations:

\left[\begin{array}{cc}car&motorcycle\\x=v_0\Delta{t}&x+d=(\frac{v_0+v_{m2}}{2}}) \Delta{t}\end{array}\right]

v_0\Delta{t}=\frac{v_0+v_{m2}}{2}\Delta{t}-d \\\frac{v_0+v_{m2}}{2}\Delta{t}-v_0\Delta{t}=d\\(v_0+v_{m2})\Delta{t}-2v_0\Delta{t}=2d\\(v_0+v_0+a\Delta{t})\Delta{t}-2v_0\Delta{t}=2d\\(2v_0+a\Delta{t})\Delta{t}-2v_0\Delta{t}=2d\\a\Delta{t}^2=2d\\\Delta{t}=\sqrt{\frac{2d}{a}}=\sqrt{\frac{2*58}{4}}=\sqrt{29}=5.385s

For the second part, we need to calculate x+d, so you can use the equation of the car to calculate x:

x = v_0\Delta{t}= 18\sqrt{29}=96.933m\\then:\\x+d = 154.933

3 0
3 years ago
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