Answer:
The starting velocity for ball 1 is 1.00 meter/second. Its ending velocity is 0.25 meter/second.
The change in velocity for ball 1 is 0.25 – 1.00 = -0.75 meter/seconds
Answer: It will increase the length of the day
Explanation: The polar ice caps contain the solid ice particles found around the polar regions,an increased temperature is a major cause of the melting of the polar ice Caps. When the polar ice caps melt especially in huge volumes they increase the amount of water flowing into the Sea this will cause a rise in the volume of the sea.
This rise in sea level will add some weights to Earth, making the Earth to rotate slightly lower than its normal speed,a slower rotation will lead to longer days.
Answer:
0.53 quart
Explanation:
The volume expansion of the coolant is gotten from ΔV = VγΔθ where ΔV = change in volume of the coolant, V = initial volume of coolant = 15 quart, γ = coefficient of volume expansion of coolant = 410 × 10⁻⁶ /°C and Δθ = temperature change = θ₂ - θ₁ where θ₁ = initial temperature of coolant = 6 °C and θ₂ = final temperature of coolant = 92 °C. So, Δθ = θ₂ - θ₁ = 92 °C - 6 °C = 86 °C
Since, ΔV = VγΔθ
substituting the values of the variables into the equation, we have
ΔV = VγΔθ
ΔV = 15 × 410 × 10⁻⁶ /°C × 86 °C
ΔV = 528900 × 10⁻⁶ quart
ΔV = 0.528900 quart
ΔV ≅ 0.53 quart
Since the change in volume of the coolant equals the spill over volume, thus the overflow from the radiator will spill into the reservoir when the coolant reaches its operating temperature of 92 °C is 0.53 quart.
Answer:
A car traveling on a highway takes to stop without skidding. What happens to its kinetic energy? ... The energy goes to parts of the brakes. No, the energy can only be reused if there is a heat pump present
Answer:
a) 166.4 s
b) (2.155 × 10⁷) s
Explanation:
15600 KWh for a year,
1 year consists of 365 × 24 hours = 8760 hours.
So, the power consumed in a year for an average household = (Energy/time)
= (15600/8760) = 1.781 KW = 1781 W
a) If the average rate of energy consumed by the house was instead diverted to lift a 1.80 × 10 3 kg car 16.8 m into the air, how long would it take
The power required for this lifting = (mgh/t)
m = 1800 kg
g = 9.8 m/s²
h = 16.8 m
t = ?
P = 1781 W
1781 = (1800×9.8×16.8)/t
t = (296,352/1781)
t = 166.4 s
b) how long would it take to lift a loaded Boeing 747 airplane, with a mass of 4.05 × 10 5 kg , to a cruising altitude of 9.67 km
The power required for this lifting = (mgh/t)
m = 405000 kg
g = 9.8 m/s²
h = 9.67 km = 9670 m
t = ?
P = 1781 W
1781 = (405000×9.8×9670)/t
t = (38,380,230,000/1781)
t = 21,549,820 s = (2.155 × 10⁷) s
Hope this Helps!!!
