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RideAnS [48]
2 years ago
7

Tina says that 3:8 is equivalent to 36:64, what did Tina do wrong

Mathematics
1 answer:
masha68 [24]2 years ago
6 0
She didn't multiple the numbers by the same nuber
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What is the function graphed below
timofeeve [1]

Answer:

y = 1/2x -2

Step-by-step explanation:

The slope of the equation is over 1 and to the right by 2 so Rise/run = 1/2

The y-intercept is -2

4 0
2 years ago
Need help with this asap, please
Lilit [14]

Answer:

<h3>             Perimeter = 3√5 + 6 + √73 + √58 + 5√2</h3>

Step-by-step explanation:

AB=\sqrt{(6-0)^2+(5-8)^2}=\sqrt{36+9}=\sqrt{45}=3\sqrt5\\\\BC=|-1-5|=|-6|=6\\\\CD=\sqrt{(-2-6)^2+(-4-(-1))^2}=\sqrt{64+9}=\sqrt{73}\\\\DE=\sqrt{(-5-(-2))^2+(3-(-4))^2}=\sqrt{9+49}=\sqrt{58}\\\\EA=\sqrt{(0-(-5))^2+(8-3)^2}=\sqrt{25+25}=\sqrt{25\cdot2}=5\sqrt2

6 0
3 years ago
Hi :) how to do question 7 ?
Gre4nikov [31]

Answer:

Step-by-step explanation:

We khow that the equation of a circle is written this way :

(x-a)²+(y-b)²=r² where (x,y) are the coordinates of the cercle's points and (a,b) the coordinates of the cercle's center and r the radius .

Our task is to khow the values of a and b :

  • We khow that the center is lying on the line 3x+2y=16⇒ 2y=-3x+16⇒ y= \frac{-3}{2}x+8  
  • We khow that the points P and Q are two points in the cercle
  • Let Ω be the center of this cercle
  • we can notice that : PΩ AND QΩ are both equal to the radius ⇒ PΩ=QΩ= r
  • So let's write the expression of this distance using vectors KHOWING THAT Ω(a,b)
  • Vector PΩ(a-4,b-6) and Vector QΩ(a-8,b-2)
  • PΩ=\sqrt{(a-4)^{2}+(b-6)^{2}  } and QΩ=\sqrt{(a-8)^{2}+(b-2)^{2}   }
  • Let's substitute a by x and b by y
  • PΩ=QΩ we substitute each distance by its expression
  • After simplyfying the expressions we get finally : -12+8x-8y=0
  • now we have -12x +8x-8y=0 and the line equation 3x+2y-16=0
  • these are simultanious equations so after solving them we get x=3.8 wich is approximatively 4 and y=2
  • we substitute a by 4 and y by 2 in PΩ to get the radius
  • we get r = \sqrt{(4-4)^{2}+(2-6)^{2}  } = 4
  • so r²= 16
  • then the equation is : (x-4)²+(y-2)²=16
5 0
3 years ago
Read 2 more answers
How can you write five9/10 as a decimal
qwelly [4]

The answer is 5.9

Hope this helps!!

7 0
3 years ago
The sum of a number times 9 and 16 is at least -26.
NARA [144]

Answer:

Step-by-step explanation:

let x be the number.

9x+16≥-26

9x≥-26-16

9x≥-42

3x≥-14

x≥-14/3

5 0
2 years ago
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