Answer:
60.9 g
Explanation:
The formula for the calculation of moles is shown below:
Given: For
Given mass = 90.1 g
Molar mass of = 17.031 g/mol
Moles of = 90.1 g / 17.031 g/mol = 5.2904 moles
Given: For
Given mass = 90.1 g
Molar mass of = 31.9988 g/mol
Moles of = 90.1 g / 31.9988 g/mol = 2.8157 moles
According to the given reaction:
4 moles of react with 5 moles of
1 mole of of react with 5/4 moles of
5.2904 moles of react with mole of
Moles of = 6.613 moles
Available moles of = 2.8157 moles
Limiting reagent is the one which is present in small amount. Thus, is limiting reagent. (2.8157 < 6.613)
The formation of the product is governed by the limiting reagent. So,
5 moles of gives 6 moles of
1 mole of gives 6/5 moles of
2.8157 moles of gives moles of
Moles of water = 3.37884 moles
Molar mass of = 18.0153 g/mol
Mass of = Moles × Molar mass = 3.37884 × 18.0153 g = 60.9 g