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dsp73
3 years ago
7

What is the molar mass for N5O9

Chemistry
1 answer:
garik1379 [7]3 years ago
5 0

Answer:

The molar mass of N5O9

is 214.0245g/mol

Explanation:

To solve this problem, we need to know each number of mole of each element present in the compound

N has 5 moles

O has 9 moles

Then, we multiple each number of mole by its number of mass of each element present

N - 14.0067

O - 15.999

Multiplying by mole

N - 5 * 14.0067 = 70.0335

O - 9 * 15.999 = 143.991

Therefore,

Molar mass of N5O9 = 70.0335 + 143.991

= 214.0245g/mol

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Answer:

0.16 atm

Explanation:

Let's look at the formula PV=nRT. First of all, T should be in kelvin, so let's add 273. Now solve for P so we get P = nRT/V.

Now let's plug these in...

P = (0.034 mol)(0.08206 L atm mol^-1 K^-1)(298 K)/5.1 L

After solving and rounding to sig figs we get 0.16 atm

5 0
2 years ago
What is the numerical value of Kc for the following reaction if the equilibrium mixture contains 0.51 M
Goryan [66]

The  numerical value  of Kc  is 1.129  x10^4

 

<u><em>  Explanation</em></u>

C3H6O +4O2→  3 CO2 + 3H2O

KC  is the ratio  of  concentration of the   product  over  the reactant.

Each concentration of  product and  reactant   are raised  to the power  of  its coefficient.

Therefore the KC  expression  of  equation above  is

Kc=[ (Co2)^3 (H2O)^3]  / [(C3H6O) (O2)^4)]

 Kc  =[(1.8^3) x  (2.0^3)] / [(0.51)  x (0.30^4)] =1.129  x10^4


3 0
3 years ago
Read 2 more answers
If a gas is initially at a pressure of nine ATM and a volume at 21 L at a temperature of 253K and the pressure is raise to 15 AT
Tom [10]

Answer:

15.0L

Explanation:

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(9*21)/253 =(15v)/ 302

v = (9*21*302)/(15*253)

v=15.0

3 0
4 years ago
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Answer:

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Explanation:

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5 0
3 years ago
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Basile [38]

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Even without specifics, my answer would be all of them.

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Technically, you need a new pair of gloves after every experiment, which is what my science teacher taught me, so all of them.

7 0
4 years ago
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