The change that would need to be made to the slit spacing in order to see a diffraction pattern is bending, because in understanding why light behaves like a wave, it is the interference and diffraction were the phenomena distinguish waves from particles but waves are the only one can interfere and diffract while particles do not. The light bends around obstacles or cylinder like waves do, then it is bending which cause and resulted in the single slit diffraction pattern.
Answer : The mass of carbon and oxygen produced is 8.83 g and 23.6 g respectively.
Explanation :
Law of conservation of mass : It states that mass can neither be created nor be destroyed but it can only be transformed from one form to another form.
This also means that total mass on the reactant side must be equal to the total mass on the product side.
The balanced chemical reaction will be,

As we are given:

According to the law of conservation of mass,
Total mass of
= Mass of
+ Mass of C
Total mass of
= 2.67 + 1 = 3.67 g
Now we have to calculate the mass of
and C.

and,

Therefore, the mass of carbon and oxygen produced is 8.83 g and 23.6 g respectively.
Answer:
The empirical formula is the simplest form;
Given:
Oxygen O at 94.1% and
H at 5.9%
Assume 100grams.
94% = 0.941 x 100gm. = 94.1 gm x 1mole/16gm. = 5.88 moles of O
5.9% = 0.059 x 100gm. = 5.9gm. X 1moleH/1.002gm. = 5.88 moles of H
There is one mole of O for each mole of H so the empirical formula is 
and written as OH.
I really hope this helps I’ve been there too and I’m just doing this so I get the 20 words and I have the picture
Answer:
A.It is the same for every sample of a single substance.
Explanation: