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juin [17]
2 years ago
11

What is the volume of a gas if 0.182 moles of the gas is at 1.99 atm and 83.4oC?

Chemistry
1 answer:
Sunny_sXe [5.5K]2 years ago
8 0

Answer:

2,67 L

Explanation:

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What volume of chlorine gas (Cl2), measured at STP, can be produced by the decomposition of 73.0g of hydrogen chloride gas (HCl)
gayaneshka [121]

Answer:

Explanation:

2HCl    =   H₂   +   Cl₂

2 mole     1 mole      1 mole

73 gram HCl = 73 / 36.5 = 2 mole of HCl

2 moles of HCl will produce 1 mole of chlorine gas .

At STP , one mole of chlorine gas has volume equal to 22.4 litre .

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A lever with a mechanical advantage greater then 1 is used to
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Give two reasons why scientists use the scientific method
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They use it because it's standerize and evidence vase
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Watch the animation depicting Rutherford’s experiment and choose which of the following conclusions are correct.a. The atom cont
Lilit [14]

Answer:

a, b, c, d

Explanation:

Rutherford’ atomic model is based on the gold foil experiment. In this experiment, beam of alpha rays was bombarded on thin gold foil. He observed that:

Most of the alpha particles passed through thin foil without any deflection.

Few alpha particles deflected by an angle of 90o.

Based on observation, Rutherford concluded that majority of the space inside the atom is empty.

He explained defection of few alpha particles by assuming that most of the mass is concentrated at the nucleus and positively charged.  

Therefore, among given, the correct statements are:

The atom contains a positively charged nucleus.

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4 0
3 years ago
What is the temperature of CO2 gas if the average speed (actually the root-mean-square speed) of the molecules is 750 m/s?
erastova [34]

Answer:

992.302 K

Explanation:

V(rms) = 750 m/s

V(rms) = √(3RT / M)

V = velocity of the gas

R = ideal gas constant = 8.314 J/mol.K

T = temperature of the gas

M = molar mass of the gas

Molar mass of CO₂ = [12 + (16*2)] = 12+32 = 44g/mol

Molar mass = 0.044kg/mol

From

½ M*V² = 3 / 2 RT

MV² = 3RT

K = constant

V² = 3RT / M

V = √(3RT / M)

So, from V = √(3RT / M)

V² = 3RT / M

V² * M = 3RT

T = (V² * M) / 3R

T = (750² * 0.044) / 3 * 8.314

T = 24750000 / 24.942

T = 992.302K

The temperature of the gas is 992.302K

Note : molar mass of the gas was converted from g/mol to kg/mol so the value can change depending on whichever one you use.

3 0
3 years ago
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