Correct, Was that a question.
The normality that would be calculated will be to high because the change in volume will be greater than the actual change in volume. if the buret tip is not filled when reading the initial volume, the actual volume should be lesser with that reading. so if you will you the higher reading the change in volume or the volume you use in titration will be higher than the actual
To solve this given problem, we can use the equation below:
ΔG=ΔH - T*ΔS
We are information and values are given and can be used in solving the ΔG of this particular reaction.
ΔH=-99.84kJ
ΔS=-16.80 J/K
T=298K
ΔG=(-99.84kJ)-(298K*-16.80J/K)
ΔG=-94.83kJ
The answer for ΔG is -94.83kJ.
Salutations!
A large gently sloping volcano with a fluid eruption is called shield volcano. The fluid is basaltic lava and the slops are gently sliding.
Hope I helped (:
Have a great day!
The formula for Kw is:
Kw= [H]*[OH]
where [H] and [OH] are
concentrations
We are given the pH so we can calculate the [H]
concentration from the formula:
pH=-log[H]
7.43 = -log[H]
[H] = 3.715x10^-8 M
In neutral solution, [H] = [OH], therefore:
<span>[OH]= 3.715x10^-8 M
Calculating Kw:
Kw = (3.715x10^-8)*( 3.715x10^-8)</span>
<span>Kw = 1.38 x 10^-15 </span>
