What mass of Ca(OH)2 is contained in 1500 mL of 0.0250 M Ca(OH)2 solution?
1 answer:
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Answer: The correct option is A.
Explanation: The given molecules are the molecules of same element.
These molecules are considered as diatomic species.
Polar molecules are the molecules in which some polarity is present in the bond. These molecules are formed when there is some difference in the electronegativities of the elements. Example: HCl
Non-polar molecules are the molecules where no polarity is present in the bond. These molecules are formed when there is no difference in the electronegativities of the elements. Example:
The given molecules are non-polar in nature.
Hence, these molecules must be non-polar. So, the correct option is A.
Correct answer: Option D, <span>K = 5.04 × 10^52
</span>
Reason:
We know that,
Ecell =
,
where n = number of electrons = 2 (in present case)
K = equilibrium constant.
Also, Ecell = <span>+1.56 v
Therefore, 1.56 = </span>
Therefore, log (K) = 52.703
Therefore, K = 5.04 X 10^52
</span>
Reason:
We know that,
Ecell =
where n = number of electrons = 2 (in present case)
K = equilibrium constant.
Also, Ecell = <span>+1.56 v
Therefore, 1.56 = </span>
Therefore, log (K) = 52.703
Therefore, K = 5.04 X 10^52
Answer:
The answer is 3.87 J/g°C
Explanation:
Here is the equation we are going to use:
C= specfic heat in J/g°C
q = heat in joules (J)
m = mass in grams (g)
T = change in temperature
Here is what is given:
q = 849 J
m = 95.4 g
T = 48.0 - 25.0 = 23°C
Find:
Specific heat capacity in J/g
The first thing we are going to do is plug everything into the equation:
Then we are going to solve for C
Hope this helps!