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saw5 [17]
3 years ago
13

Which is the second step in the dissolving process?

Chemistry
2 answers:
worty [1.4K]3 years ago
8 0

Answer : The correct option is, The solvent molecules surround the solute particles.

Explanation :

Dissolving process : It is defined as the process in which solute particles interact with solvent molecules.

When solute particles comes in contact with the solvent particles, firstly the solute particles break down into ions and this result in the Lattice energy of the solute particles.

When solute particles break down, it gets surrounded with the solvent particles and it results in the Hydration enthalpy of the particles.

Hence, the second step of dissolving process is when solvent molecules surround the solute molecules.

geniusboy [140]3 years ago
8 0

Answer:

C). The solvent molecules surround the solute particles.

Explanation:

I just took the quiz

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What is the pH of a solution with an H3O+ concentration of 5.67 x 10-4 M?
Valentin [98]

Answer:

<h2>3.25 </h2>

Explanation:

The pH of a solution can be found by using the formula

pH = - log [ { H_3O}^{+}]

From the question we have

ph =  -  log(5.67 \times  {10}^{ - 4} )  \\  = 3.2464

We have the final answer as

<h3>3.25 </h3>

Hope this helps you

3 0
3 years ago
1. For each of the molecules below, determine the electron geometry, molecule geometry, and bond
Alexxx [7]

Answer:

CCl4- tetrahedral bond angle 109°

PF3 - trigonal pyramidal bond angles less than 109°

OF2- Bent with bond angle much less than 109°

I3 - linear with bond angles = 180°

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Explanation:

Valence shell electron-pair repulsion theory (VSEPR theory) helps us to predict the molecular shape, including bond angles around a central atom, of a molecule by examination of the number of bonds and lone electron pairs in its Lewis structure. The VSEPR model assumes that electron pairs in the valence shell of a central atom will adopt an arrangement which tends to minimize repulsions between these electron pairs by maximizing the distance between them. The electrons in the valence shell of a central atom are either bonding pairs of electrons, located primarily between bonded atoms, or lone pairs. The electrostatic repulsion of these electrons is reduced when the various regions of high electron density assume positions as far apart from each other as possible.

Lone pairs and multiple bonds are known to cause more repulsion than single bonds and bond pairs. Hence the presence of lone pairs or multiple bonds tend to distort the molecular geometry geometry away from that predicted on the basis of VSEPR theory. For instance CCl4 is tetrahedral with no lone pair and four regions of electron density around the central atom. This is the expected geometry. However OF2 also has four regions of electron density but has a bent structure. The molecule has four regions of electron density but two of them are lone pairs causing more repulsion. Hence the observed bond angle is less than 109°.

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5 0
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Answer:

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Hope this helps.

3 0
3 years ago
How does melting order relate to melting point?
KatRina [158]

Answer:

I think A.

Explanation:I say A because of the substance melting the quicking does have the highest melting point because its the highest.

5 0
3 years ago
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