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saw5 [17]
2 years ago
13

Which is the second step in the dissolving process?

Chemistry
2 answers:
worty [1.4K]2 years ago
8 0

Answer : The correct option is, The solvent molecules surround the solute particles.

Explanation :

Dissolving process : It is defined as the process in which solute particles interact with solvent molecules.

When solute particles comes in contact with the solvent particles, firstly the solute particles break down into ions and this result in the Lattice energy of the solute particles.

When solute particles break down, it gets surrounded with the solvent particles and it results in the Hydration enthalpy of the particles.

Hence, the second step of dissolving process is when solvent molecules surround the solute molecules.

geniusboy [140]2 years ago
8 0

Answer:

C). The solvent molecules surround the solute particles.

Explanation:

I just took the quiz

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Which of the following is the best way to separate sugar from water?
kompoz [17]
I don't know the options but usually a small strainer or a coffee thing u put over a cup and let the water seep down and the sugar stays.
4 0
3 years ago
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Imagine mixing 1 tablespoon of Epsom salt with 2 cups of ammonia. How much precipitate would be produced? Describe the amount of
barxatty [35]

The amount of precipitate produced will be proportional to the amount of NH₃ reacted with water to produce NH₄OH.

<h3>What is precipitate?</h3>

Precipitates are the crystal type formation, when the solute is no more dissolving in the solvent.

Imagine mixing 1 tablespoon of Epsom salt with 2 cups of ammonia, the reaction is

2NH₃ + MgSO₄ + 2H₂O → Mg(OH)₂ + (NH₄)₂SO₄

The amount of precipitate produced will be proportional to the amount of NH₃ reacted with water to produce NH₄OH.

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4 0
1 year ago
Calculate the mass of H2OH2O produced by metabolism of 2.4 kgkg of fat, assuming the fat consists entirely of tristearin (C57H11
otez555 [7]

Answer:

2,669.58 grams of water will be produced by metabolism of 2.4 kilogram of fat.

Explanation:

2C_{57}H_{110}O_6+163O_2\rightarrow 114CO_2+110H_2O

Mass of fat = 2.4 kg = 2.4 × 1000 g = 2400 g

1 kg = 1000 g

Molar mass of fat = M

M = 57 × 12 g/mol + 110 × 1 g/mol+ 6 × 16 g/mol = 890 g/mol[/tex]

Moles of fat = \frac{2400 g}{890 g/mol}=2.6966 mol

According to reaction , 2 moles of fat gives 110 moles of water. Then 2.6966 moles of fat will give  ;

\frac{110}{2}\times 2.6966 mol=148.31 mol of water

Mass of 148.31 moles of water ;

148.31 mol × 18 g/mol = 2,669.58 g

2,669.58 grams of water will be produced by metabolism of 2.4 kilogram of fat.

8 0
2 years ago
What is the ph of a 0.25 m solution of c6h5nh2 given that its kb is 1.8 x 10-6?
IrinaK [193]

The pH a 0.25 m solution of C₆H₅NH₂ is equal to 3.13.

<h3>How do we calculate pH of weak base?</h3>

pH of the weak base will be calculate by using the Henderson Hasselbalch equation as:

pH = pKb + log([HB⁺]/[B])

pKb = -log(1.8×10⁻⁶) = 5.7

Chemical reaction for C₆H₅NH₂ is:

                          C₆H₅NH₂ + H₂O → C₆H₅NH₃⁺ + OH⁻

Initial:                     0.25                           0            0

Change:                    -x                             x             x

Equilibrium:        0.25-x                           x             x

Base dissociation constant will be calculated as:
Kb = [C₆H₅NH₃⁺][OH⁻] / [C₆H₅NH₂]

Kb = x² / 0.25 - x

x is very small as compared to 0.25, so we neglect x from that term and by putting value of Kb, then the equation becomes:

1.8×10⁻⁶ = x² / 0.25

x² = (1.8×10⁻⁶)(0.25)

x = 0.67×10⁻³ M = [C₆H₅NH₃⁺]

On putting all these values on the above equation of pH, we get

pH = 5.7 + log(0.67×10⁻³/0.25)

pH = 3.13

Hence pH of the solution is 3.13.

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What is a ‘control’ in an experiment?
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The answer fo this is D because of the person controlling the outcome for both variables

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