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3 years ago

Yu, Nailah, and Elena each bought between 7

Mathematics

2 answers:

77julia77 [94]3 years ago

6 0

Answer:

The length of ribbons is missing. However I am trying my best to answer the question.

First ribbon is 5/2 = 2.5 yd.

Second ribbon is 4/5 = 0.8 yd.

Third ribbon is 7/2 =3.5 yd.

Step-by-step explanation:

The length of ribbons is missing. However I am trying my best to answer the question.

First ribbon is 5/2 = 2.5 yd.

Second ribbon is 4/5 = 0.8 yd.

Third ribbon is 7/2 =3.5 yd.

Purchased 2 * first ribbon 5 yd 2.5 yd * 2 ribbons

and 1 * third ribbon 3.5 yd

altogether Yu purchased 8.5 yards of ribbon

Nailah

Purchased 1 * 2.5 ribbon

3 * 0.8 ribbon

and 1 * 3.5 ribbon

altogether Nailah purchased 8.4 yards of ribbon

Yu bought 3 pieces of ribbon. Nailah bought 5 pieces of ribbon. Elena bought 6 pieces of ribbon. The lengths of ribbons are given below.

Elena

Purchased 2 * 2.5 ribbon

and 4 * 0.8 ribbon

altogether Elena purchased 8.2 yards of ribbon.

Anastaziya [24]3 years ago

6 0

Answer:

The length of ribbons is missing. However I am trying my best to answer the question.

First ribbon is 5/2 = 2.5 yd.

Second ribbon is 4/5 = 0.8 yd.

Third ribbon is 7/2 =3.5 yd.

Step-by-step explanation:

The length of ribbons is missing. However I am trying my best to answer the question.

First ribbon is 5/2 = 2.5 yd.

Second ribbon is 4/5 = 0.8 yd.

Third ribbon is 7/2 =3.5 yd.

Purchased 2 * first ribbon 5 yd 2.5 yd * 2 ribbons

and 1 * third ribbon 3.5 yd

altogether Yu purchased 8.5 yards of ribbon

Nailah

Purchased 1 * 2.5 ribbon

3 * 0.8 ribbon

and 1 * 3.5 ribbon

altogether Nailah purchased 8.4 yards of ribbon

Yu bought 3 pieces of ribbon. Nailah bought 5 pieces of ribbon. Elena bought 6 pieces of ribbon. The lengths of ribbons are given below.

Elena

Purchased 2 * 2.5 ribbon

and 4 * 0.8 ribbon

altogether Elena purchased 8.2 yards of ribbon.

Step-by-step explanation:

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Gabriel is signing up for a gym membership with a one-time fee to join and then a

polet [3.4K]

Answer:

$C= 40t+100$

Step-by-step explanation:

In this exercise, we want to model an equation to represent the cost that Gabriel will when registering with a gym.

from the given information, we can model the cost after the equation of a straight line

y= mx+c

so "C" is the cost, while $40 is a fee dependent on "t" the number of months subscribed

and $100 is the joining fee, which is a constant term

$C= 40t+100$

4 0

3 years ago

What is 23 divided by 19,386

NNADVOKAT [17]

Answer:

0.0011864232 I think

8 0

3 years ago

Read 2 more answers

Encuentre el radio y el área de círculos cuya circunferencias tienen las siguientes medidas

Vadim26 [7]

Answer:

Los radios de los círculos son $r_{1} \approx 9.995$ , $r_{2} \approx 2.013$ , $r_{3} \approx 7.592$ , respectivamente.

Las áreas de los círculos son $A_{1} \approx 313.845$ , $A_{2} \approx 12.730$ , $A_{3} \approx 181.077$ , respectivamente.

Step-by-step explanation:

La circunferencia ( $s$ ) se calcula mediante la siguiente fórmula:

$s = 2\pi\cdot r$ (1)

Donde $r$ es el radio del círculo.

Una vez hallado el radio, se determina el área de la figura geométrica ( $A$ ) mediante la siguiente fórmula:

$A = \pi\cdot r^{2}$ (2)

Si conocemos que las circunferencias son $s_{1} = 62.8$ , $s_{2} = 12.65$ y $s_{3} = 47.7$ , respectivamente:

1) Radios de los círculos

$r_{1} = \frac{s_{1}}{2\pi}$ , $r_{2} = \frac{s_{2}}{2\pi}$ , $r_{3} = \frac{s_{3}}{2\pi}$

$r_{1} \approx 9.995$ , $r_{2} \approx 2.013$ , $r_{3} \approx 7.592$

2) Áreas de los círculos

$A_{1} = \pi\cdot r_{1}^{2}$ , $A_{2} = \pi\cdot r_{2}^{2}$ , $A_{3} = \pi\cdot r_{3}^{2}$

$A_{1} \approx 313.845$ , $A_{2} \approx 12.730$ , $A_{3} \approx 181.077$

6 0

3 years ago

So,some please help me with this question !

Tamiku [17]

$\qquad \qquad \bf \huge\star \: \: \large{ \underline{Answer} } \huge \: \: \star$

$\qquad❖ \: \sf \: \angle C = 63 \degree$

$\textsf{ \underline{\underline{Steps to solve the problem} }:}$

$\qquad❖ \: \sf \:x + 4x + 12 + x=180°$

( Angle EBA= Angle DBC, and the three angles sum upto 180° due to linear pair property )

$\qquad❖ \: \sf \:6x + 12 = 180$

$\qquad❖ \: \sf \:6x = 180 - 12$

$\qquad❖ \: \sf \:6x = 168$

$\qquad❖ \: \sf \:x = 28 \degree$

Next,

$\qquad❖ \: \sf \: \angle C + \angle D + x = 180°$

$\qquad❖ \: \sf \: \angle C +3x + 5 + x = 180°$

$\qquad❖ \: \sf \: \angle C +4x = 180 - 5$

$\qquad❖ \: \sf \: \angle C +4(28) = 175$

( x = 28° )

$\qquad❖ \: \sf \: \angle C +112 = 175$

$\qquad❖ \: \sf \: \angle C = 175 - 112$

$\qquad❖ \: \sf \: \angle C = 63 \degree$

$\qquad \large \sf {Conclusion} :$

$\qquad❖ \: \sf \: \angle C = 63 \degree$

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1 year ago

Read 2 more answers

Math help!!! Can somebody answer 1&2.

gregori [183]

Answer:

1) MON 2) MPO

Step-by-step explanation:

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3 years ago