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iren [92.7K]
3 years ago
11

Yu, Nailah, and Elena each bought between 7

Mathematics
2 answers:
77julia77 [94]3 years ago
6 0

Answer:

The length of ribbons is missing. However I am trying my best to answer the question.

First ribbon is 5/2 = 2.5 yd.

Second ribbon is 4/5 = 0.8 yd.

Third ribbon is 7/2 =3.5 yd.

Step-by-step explanation:

The length of ribbons is missing. However I am trying my best to answer the question.

First ribbon is 5/2 = 2.5 yd.

Second ribbon is 4/5 = 0.8 yd.

Third ribbon is 7/2 =3.5 yd.

Yu

Purchased 2 * first ribbon 5 yd   2.5 yd * 2 ribbons

and 1 * third ribbon 3.5 yd

altogether Yu purchased 8.5 yards of ribbon

Nailah

Purchased 1 * 2.5 ribbon

3 * 0.8 ribbon

and 1 * 3.5 ribbon

altogether Nailah purchased 8.4 yards of ribbon

Yu bought 3 pieces of ribbon. Nailah bought 5 pieces of ribbon. Elena bought 6 pieces of ribbon. The lengths of ribbons are given below.

Elena

Purchased 2 * 2.5 ribbon

and 4 * 0.8 ribbon

altogether Elena purchased 8.2 yards of ribbon.

Anastaziya [24]3 years ago
6 0

Answer:

The length of ribbons is missing. However I am trying my best to answer the question.

First ribbon is 5/2 = 2.5 yd.

Second ribbon is 4/5 = 0.8 yd.

Third ribbon is 7/2 =3.5 yd.

Step-by-step explanation:

The length of ribbons is missing. However I am trying my best to answer the question.

First ribbon is 5/2 = 2.5 yd.

Second ribbon is 4/5 = 0.8 yd.

Third ribbon is 7/2 =3.5 yd.

Yu

Purchased 2 * first ribbon 5 yd   2.5 yd * 2 ribbons

and 1 * third ribbon 3.5 yd

altogether Yu purchased 8.5 yards of ribbon

Nailah

Purchased 1 * 2.5 ribbon

3 * 0.8 ribbon

and 1 * 3.5 ribbon

altogether Nailah purchased 8.4 yards of ribbon

Yu bought 3 pieces of ribbon. Nailah bought 5 pieces of ribbon. Elena bought 6 pieces of ribbon. The lengths of ribbons are given below.

Elena

Purchased 2 * 2.5 ribbon

and 4 * 0.8 ribbon

altogether Elena purchased 8.2 yards of ribbon.

Step-by-step explanation:

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I need help on how to understand this problem
dangina [55]

Answer:

1/6.2

Step-by-step explanation:

1/(2+3 square root 2)

2+4.24264068712=6.24264068712

6.24264068712 Rounded to the nearest tenth is 6.2

1/6.2

Hope this helps.

4 0
4 years ago
20 POINTS
docker41 [41]

answer : option C

f(x) = x^3 + x^2 - 8x - 8

Lets find the number of zeros by factoring

0 = x^3 + x^2 - 8x - 8

Group first two terms and last two terms

0 = (x^3 + x^2) (- 8x - 8)

Factor out GCF from each group

0 = x^2(x + 1)-8(x + 1)

0 = (x^2-8)(x + 1)

Now we set each factor =0 and solve for x

0 = (x^2-8)             and   (x + 1)=0

x^2 = 8            and x = -1

x= 2+-\sqrt{2}     and x= -1

So we have three real zeros

The function has three real zeros. The graph of the function intersects the x-axis at exactly three locations.

8 0
4 years ago
Solve.
STALIN [3.7K]

Answer:

60.

Step-by-step explanation:

2/5 equals 0.4.

150 divided by 10 equals 15. times 15 by 4 to get 60.

5 0
4 years ago
Read 2 more answers
What are the zeros of f(x) = x^2 - 12x+ 36
yuradex [85]

Answer:

x = 6

Step-by-step explanation:

0 = x^2 -12x + 36      solve by factoring ...or Quadratic Formula

0 = ( x-6)(x-6)       shows zeroes ( both of them) are x = 6

4 0
2 years ago
The Northwest High School senior class decided to host a raffle to raise money for their senior trip. They charged $2 for each s
prisoha [69]
Let x be the tickets that the adults bought, andy be the tickets that children bought.
From the problem we have the system of linear equations:
\left \{ {{2x+5y=2686} \atop {y=3x}} \right.

The first thing we are going to do to solve our system, is replacing equation (2) in equation (1), and  then, solve for x
2x+5y=2686
2x+5(3x)=2686
2x+15x=2686
17x=2686
x= \frac{2686}{17}
x=158

Now that we have the number of tickets that the adults bought, lets replace that value in equation (2):
y=3x
y=3(158)
y=474

Last but not least, to find the total number of tickets, we are going to add x and y:
158+474=632

We can conclude that <span>Northwest High School's senior class sold 632 raffle tickets.</span>
7 0
3 years ago
Read 2 more answers
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