Explanation:
We know that Ionic radius increases on going downwards in any group. In group 15, the last elements Sb and Bi have ionic radii lesser than the rest of its elements i.e N,P and As.
This is due to the fact that Sb and Bi have completely filled d and f sub-shells which have least shielding effect.
Thus, they do not guard the valence electrons to a greater extent due to which the valence electrons feel almost whole nuclear charge.
This, results into attraction of valence electrons towards nucleus and hence size decreases.
This follows a simple conversion technique. Basically what the question is trying to say here is to convert 29.1 inHg to mmHg. 1 inHg is equal to 25.4 mmHg so 29.1 inHg would be equal to which when evaluated turns out to be: . :D
The molar concentration of the potassium hydroxide solution was 0.815 mol/L.
<em>Balanced equation</em>: 2KOH + H_2SO_4 → K_2SO_4 + 2H_2O
<em>Moles of H_2SO_4</em>:
15.1 mL H_2SO_4 × (1.50 mmol H_2SO_4 /1 mL H_2SO_4)
= 22.65 mmol H_2SO_4
<em>Moles of KOH</em>: 22.65 mmol H_2SO_4× (2 mmol KOH/2 mmol H_2SO_4)
= 45.30 mmol KOH
<em>Concentration of KOH</em>: c= "moles"/"litres" = 45.30 mmol/55.6 mL
= 0.815 mol/L
The answer is c this is the answer
The method that can be used to separate the mixture is chromatography.
<h3>
What is chromatography?</h3>
"Chromatography" is obtained form a Greek word which literarily means, color writing. It is a method of separation which is common in separating a mixture of pigments.
To obtain the colors used, two solvents are mixed and the sample ink is dissolved in the solvents then spotted on a thin layer and put into a TLC chamber then the chromatogram is allowed to develop.
The various components of the pigment will appear on the chromatogram and can be identified using spectrophotometry. The Rf values of each component can also be used to identify it.'
Learn more about chromatography: brainly.com/question/26491567