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sukhopar [10]
3 years ago
14

Climate changes cause a drought. There is no food to collect. To survive, the animals must become predators, catch and kill prey

for food. Which group(s) would you expect to die out because of their mutations in this new environment? A) Group B, D, E B) Groups E, F, G C) All of the groups. D) Groups B, D, E, F, G
Chemistry
2 answers:
o-na [289]3 years ago
8 0
I think the answer you are looking for is D.

Hope this helps!!! :D
gregori [183]3 years ago
7 0

D) Groups B, D, E, F, G

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Solids have:<br> fixed shape<br> O A and B<br> fixed size<br> neither A nor B
Lemur [1.5K]

<u>Answer:</u>

<em>B. A and B</em>

<em></em>

<u>Explanation:</u>

1. Solids have a definite volume, definite size and definite shape

2. The particles present in a solid are very closely packed since the intermolecular forces between them are very strong. The molecules do not move apart.

3. Melting point is the temperature at which solid changes into a liquid.

4. When a solid is heated to the melting point the intermolecular forces are overcome by the energy and the molecules present in it moves from its fixed position to take its liquid state which is called as melting.

8 0
3 years ago
True or false A compound can consist of one kind of element?
slavikrds [6]
False because a compound is one or more elements
6 0
3 years ago
How many atoms are in 0.065 grams of Cadmium?
lilavasa [31]
D.
because that can only be the answer
8 0
3 years ago
A chemist prepares a solution of copper(II) fluoride by measuring out of copper(II) fluoride into a volumetric flask and filling
Simora [160]

The question is incomplete, here is the complete question.

A chemist prepares a solution of copper(II) fluoride by measuring out 0.0498 g of copper(II) fluoride into a 100.0mL volumetric flask and filling the flask to the mark with water.

Calculate the concentration in mol/L of the chemist's copper(II) fluoride solution. Round your answer to 3 significant digits.

<u>Answer:</u> The concentration of copper fluoride in the solution is 4.90\times 10^{-3}mol/L

<u>Explanation:</u>

To calculate the molarity of solute, we use the equation:

\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}

We are given:

Given mass of copper (II) fluoride = 0.0498 g

Molar mass of copper (II) fluoride = 101.54 g/mol

Volume of solution = 100.0 mL

Putting values in above equation, we get:

\text{Molarity of copper (II) fluoride)=\frac{0.0498\times 1000}{101.54\times 100.0}\\\\\text{Molarity of copper (II) fluoride}=4.90\times 10^{-3}mol/L

Hence, the concentration of copper fluoride in the solution is 4.90\times 10^{-3}mol/L

4 0
3 years ago
What is the conjugate acid in the following equation hbr + H2O yields h30 positive + BR negative
kirill115 [55]

Answer:

HBr + H2O = H3O+ + Br-

So our conjugate acid is the H3O+ to H2O

Explanation:

A conjugate acid of a base results when the base accepts a proton.

Consider ammonia reacting with water to form an equilibrium with ammonium ions and hydroxide ions:

NH3 (aq) + H2O (l) ⇌ NH4+ (aq) + OH- (aq)

Ammonium, NH4+, acts as a conjugate acid to ammonia, NH3.

3 0
3 years ago
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