Answer:
58mL
Explanation:
Given parameters:
Density of water = 1g/mL
Mass of object = 58g
Unknown:
The volume the object must have to be able to float in water = ?
Solution:
To solve this problem, we know that the object must have density value equal to that of water or less than that of water to be able to float.
We then set its density to that of water;
Density =
Volume =
So;
Volume =
= 58mL
Answer: 1. CaO + H2O => Ca(OH)2
2. P4 + 5O2 => 2P2O5
3. 2 Ca + O2 => 2 CaO
4. 8 Cu + S8 => 8 CuS
5. CaO + H2O => Ca(OH)2
6. S8 + 8 O2 => 8 SO2
7. 3 H2 + N2 => 2 NH3
8. H2 + Cl2 =>2 HCl
9. 16 Ag + S8 => 8 Ag2S
10. Cr + O2 => 2Cr2O3
11. 2Al + 3Br2 => 2AlBr3
12. 2Na + I2 => 2NaI
13. 2H2 + O2 =>2 H2O
14. 4 Al + 3O2 => 2 Al2O3
Explanation:
The negative side of another magnet
Its period 5 from 5s25p6, with Xenon(54) as the noble gas. 2+6 = 8 electrons
54+8 = 62, or Sm.
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Preparation of ethanoic acid from ethane This free online course covers the preparation of ethanoic acid from ethane. The Contents tab displays all the lessons ...
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