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3 years ago

7

Dayand picked apples 42 hours sleep at 28 apples in the first hour and at the end of 2 hours she had 49 how many apples did she

pick during the second hour

1 answer:

SCORPION-xisa [38]3 years ago

6 0

Subtract 28 from 49 which is 21 picked in the second hour

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45 POINTS PLEASE HELP!

andrew-mc [135]

Hello,

Question:

Jack popped some popcorn, but 3 of the 150 kernels did not pop.

Determine which popcorn snacks below has the same ratio of unpopped to total kernels as Jack's popcorn.

We Know:

3 out of 150 did not pop

Solution:

3/150 = 3 to 150

Find ratios similar to this one,

4/200

2/100

1/50

So now we know for every kernel that dosent pop there are 50 that did.

Answers:

4 unpopped out of 200 kernels

1 unpopped out of 50 kernels

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4 years ago

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21 times 9 equals 9 times 21 what is the property

Reil [10]

Commutative property....

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The answer is B $37.59
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3 years ago

Which models show 40%? Check all that apply. A model with 4 shaded sections and 6 unshaded sections. A model with 40 shaded sect

Amanda [17]

Answer:

A model with 4 shaded sections and 6 unshaded sections.

A model with 40 shaded sections and 60 unshaded sections.

Step-by-step explanation:

Required:

Which models shows 40%

(a) 4 shaded and 6 unshaded

First, we calculate the total sections

$Total = 4 + 6$

$Total = 10$

The percentage of the shaded section is:

$Shaded = \frac{4}{10} * 100\%$

$Shaded = 0.4 * 100\%$

$Shaded = 40\%$

(b) 40 shaded and 60 unshaded

First, we calculate the total sections

$Total = 40 + 60$

$Total = 100$

The percentage of the shaded section is:

$Shaded = \frac{40}{100} * 100\%$

$Shaded = 0.4 * 100\%$

$Shaded = 40\%$

(c) 2 shaded and 8 unshaded

First, we calculate the total sections

$Total = 2 + 8$

$Total = 10$

The percentage of the shaded section is:

$Shaded = \frac{2}{10} * 100\%$

$Shaded = 0.2 * 100\%$

$Shaded = 20\%$

<em>Hence, (a) and (b) shows 40%</em>

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3 years ago

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What substitution Should be used to re-write 26(x^3+1)^2-22(x^3+1)-3=0 as a quadratic function?

mel-nik [20]

Answer:

$x^3+1$

Step-by-step explanation:

$26(x^3+1)^2-22(x^3+1)-3=0$

Comparing to

$A(u)^2+B(u)+C =0$

Where A,B,C are constants

You should see that we need to substitute the $x^3+1$ with u.

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3 years ago