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2 years ago

7

Dayand picked apples 42 hours sleep at 28 apples in the first hour and at the end of 2 hours she had 49 how many apples did she

pick during the second hour

1 answer:

SCORPION-xisa [38]2 years ago

6 0

Subtract 28 from 49 which is 21 picked in the second hour

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A bag contains the letters from the words SUMMER VACATION. You randomly choose a letter A, and do not replace it. Then you choos

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<h3>Hello there i hope you are having a good day :) Your question : A bag contains the letters from the words SUMMER VACATION. You randomly choose a letter A, and do not replace it. Then you choose another letter A. What is the probability that both letters are A’s? Write your answer as a percent, with the percent symbol. If needed, round to the nearest tenth. </h3><h3>Firstly the word is SUMMER VACATION there are 14 letters in this word and 2 of them with the letter A So this would be 2/14 and 1/7 Then there is 13 letters because we used one already so it would be 1/13 Then the second A would equal 1/13 and this would be 1/7 and 1/13 you would times both given 1/91 now written that in percent with a percent symbol 1.0989011% So this would be 1.91%</h3><h3>Hopefully that helps you ❤</h3>

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2 years ago

Help I’m doing a test !!!!!

Helga [31]

Answer:

it will be 3/4

Step-by-step explanation:

that what i thank it is.

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2 years ago

Read 2 more answers

Define highest common factor

wariber [46]

Answer:

Of two numbers, The largest whole number which is a factor of both.

Step-by-step explanation:

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2 years ago

Suppose that S is the set of successful students in a classroom, and that F stands for the set of freshmen students in that clas

lora16 [44]

Answer:

b) 24

Step-by-step explanation:

We solve building the Venn's diagram of these sets.

We have that n(S) is the number of succesful students in a classroom.

n(F) is the number of freshmen student in that classroom.

We have that:

$n(S) = n(s) + n(S \cap F)$

In which n(s) are those who are succeful but not freshmen and $n(S \cap F)$ are those who are succesful and freshmen.

By the same logic, we also have that:

$n(F) = n(f) + n(S \cap F)$

The union is:

$n(S \cup F) = n(s) + n(f) + n(S \cap F)$

In which

$n(S \cup F) = 58$

$n(s) = n(S) - n(S \cap F) = 54 - n(S \cap F)$

$n(f) = n(F) - n(S \cap F) = 28 - n(S \cap F)$

So

$n(S \cup F) = n(s) + n(f) + n(S \cap F)$

$58 = 54 - n(S \cap F) + 28 - n(S \cap F) + n(S \cap F)$

$n(S \cap F) = 24$

So the correct answer is:

b) 24

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3 years ago

85 : 45 = 170 : x<br><br> Answer to get the answer for x

Marina86 [1]

x=9/34 that's the answer

8 0

2 years ago