What charge does an atom have when electrons are lost from the atom?

Consider two massless springs connected in series. Spring 1 has a spring constant k1, and spring 2 has a spring constant k2. A c

Andru [333]

Answer:

a. k = (1/k₁ + 1/k₂)⁻¹ b. k = (1/k₁ + 1/k₂ + 1/k₃)⁻¹

Explanation:

Since only one force F acts, the force on spring with spring constant k₁ is F = k₁x₁ where x₁ is its extension

the force on spring with spring constant k₂ is F = k₂x₂ where x₁ is its extension

Let F = kx be the force on the equivalent spring with spring constant k and extension x.

The total extension , x = x₁ + x₂

x = F/k = F/k₁ + F/k₂

1/k = 1/k₁ + 1/k₂

k = (1/k₁ + 1/k₂)⁻¹

B

The force on spring with spring constant k₃ is F = k₃x₃ where x₃ is its extension

Let F = kx be the force on the equivalent spring with spring constant k and extension x.

The total extension , x = x₁ + x₂ + x₃

x = F/k = F/k₁ + F/k₂ + F/k₃

1/k = 1/k₁ + 1/k₂ + 1/k₃

k = (1/k₁ + 1/k₂ + 1/k₃)⁻¹

8 0

3 years ago

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Two moles of neon gas at 25oC and 2.0 atm is expanded to 3 times the original volume while the pressure is reduced to 1.0 atm. F

bazaltina [42]

Answer:

The end temperature is 174 °C

Explanation:

Ideal gases are a simplification of real gases that is done to study them more easily. It is considered to be formed by point particles, do not interact with each other and move randomly. It is also considered that the molecules of an ideal gas, in themselves, do not occupy any volume.

The pressure, P, the temperature, T, and the volume, V, of an ideal gas, are related by a simple formula called the ideal gas law:

P*V = n*R*T

where P is the gas pressure, V is the volume that occupies, T is its temperature, R is the ideal gas constant, and n is the number of moles of the gas.

So, being:

P= 2 atm
V=?
n= 2 moles
R= 0.082 $\frac{atm*L}{mol*K}$
T= 25 °C= 298 °K

and replacing:

2 atm*V= 2 moles* 0.082 $\frac{atm*L}{mol*K}$ *298 K

you get:

$V=\frac{2 moles* 0.082\frac{atm*L}{mol*K} *298 K}{2 atm}$

V= 24.436 L

Now, two moles of neon gas is expanded to 3 times the original volume while the pressure is reduced to 1.0 atm. Then you know:

P= 1 atm
V= 3*24.436 L=73.308 L

n= 2 moles
R= 0.082 $\frac{atm*L}{mol*K}$
T= ?

Replacing:

1 atm*73.308 L= 2 moles* 0.082 $\frac{atm*L}{mol*K}$ *T

Solving:

$T=\frac{1 atm*73.308 L}{2 moles* 0.082\frac{atm*L}{mol*K}}$

T= 447 °K= 174 °C (being 0°C=273 °K)

The end temperature is 174 °C

5 0

3 years ago

N asteroid of mass 58,000 kg carrying a negative charge of 15 μc is 180 m from a second asteroid of mass 52,000 kg carrying a ne

Deffense [45]

For this problem, we use the Coulomb's Law. The working equation is written below:

F = kQ₁Q₂/d²
where
F is the electric force
k is a constant equal to 8.99 × 10⁹ N • m²/C²
Q is the charges for the two objects
d is he distance between the objects

Substituting the values,
F = (8.99 × 10⁹ N • m²/C²)(-15×10⁻⁶ C)(-11×10⁻⁶ C)/(180²)
F = 4.578×10⁻⁵ N

Next, we determine the gravitational force using the Law of Universal Gravitation:

F = Gm₁m₂/d²
where
F is the gravitational force
G is a constant equal to 6.67 × 10⁻¹¹ N • m²/kg²
m is the masses of the objects
d is the distance between the objects

F = (6.67 × 10⁻¹¹ N • m²/kg²)(58,000 kg)(52,000 kg)/(180²)
F = 6.2089×10⁻⁶ N

The sum of the two forces equal the net force:
Net force = 4.578×10⁻⁵ N + 6.2089×10⁻⁶ N = 1.079×10⁻⁵ N

6 0

3 years ago

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The molecular mass of sodium oxide (Na2O) is

tresset_1 [31]

The answer is 62 u. The molecular mass of a molecule (Mr) is the sum of atomic masses (Ar) of its elements. Ar(Na) = 23 u. Ar(O) = 16 u. Therefore, the molecular mass of sodium oxide is 62 u: Mr(Na2O) = 2 * Ar(Na) + Ar(O) = 2 * 23 u + 16 u = 46 + 16 = 62 u.

7 0

4 years ago

Describe how the resistance of the filament lamp changes as the current through it increases.

pochemuha

This heats up when an electric current passes through it, and produces light as a result. The resistance of a lamp increases as the temperature of its filament increases. The current flowing through a filament lamp is not directly proportional to the voltage across it.

8 0

3 years ago