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xz_007 [3.2K]
3 years ago
8

A rocket moves through outer space at 11,000 m/s. At this rate, how much time would be required to travel the distance from Eart

h to Moon, which is 380,000 km?
Physics
1 answer:
Charra [1.4K]3 years ago
5 0
11,000 m = 11 km

11 km/s over 380,000km

380,000 / 11 = 34545.4 seconds

34545.4 / 60 = 575.7 minutes
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Is static electricity positive or negative? Explain
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T<span>he phenomenon of </span>static electricity<span> requires a separation of </span>positive<span> and </span>negative<span> charges. When two materials are in contact, electrons may move from one material to the other, which leaves an excess of </span>positive<span>charge on one material, and an equal </span>negative<span> charge on the other.</span>
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A wire with a mass of 1.14 g/cm is placed on a horizontal surface with a coefficient of friction of 0.200. The wire carries a cu
anzhelika [568]

Answer: B=0.0162T

Explanation:

let this sign be ∅ (titha in degrees)

let coefficient of friction of 0.200 be u

and i be current i= 1.41A

mass m=1.14g/cm m=0.0114g/m

To find the magnetic field from the north will be:

tan ∅= u

∅=tan^{-1}(0.200

∅=11.3°

The direction:

i L*B cos(∅)=  umg

divide both by iLcos(∅) to find B

B= \frac{umg}{iBcos(∅)}  where m=\frac{m}{L}

B= \frac{u(m/L)g}{icos(∅)}

B= \frac{0.200*0.0114*9.81}{1.41*cos(11.3)}

B=0.0162T

7 0
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3. Which form of radiation is used to kill microorganisms?
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Answer:

d

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4 0
3 years ago
What four regions of the electromagnetic spectrum
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3 years ago
A wave pulse travels along a string at a speed of 200 cm/s. What will be the speed if:
34kurt

Answer:

a) v_f = \sqrt{\frac{2TL}{m}} = \sqrt{2} v = \sqrt{2}2m/s =2.83 m/s

The velocity increase by a factor of \sqrt{2}

b) v_f = \sqrt{\frac{TL}{4m}} = \frac{1}{2} v = \frac{1}{2} *2m/s =1 m/s

The velocity decrease by a factor of 2.

c) v_f = \sqrt{\frac{4TL}{m}} = 2} v = 2 *2m/s =4m/s

The velocity increase by a factor of 2

d) v_f = \sqrt{\frac{4TL}{4m}} = v = 2m/s

The velocity not changes.

Explanation:

For this case we know that the velocity is v = 200 cm/s = 2m/s

v_f represent the final velocity after the changes specified,

Part a

The formula for the speed of a wave in a string is given by:

v = \sqrt{\frac{T}{\rho}}

And the linear density is defined as:

\rho = \frac{m}{L}

And if we replace this we got:

v = \sqrt{\frac{TL}{m}}

If the tension mass is doubled we have this:

v_f = \sqrt{\frac{2TL}{m}} = \sqrt{2} v = \sqrt{2}2m/s =2.83 m/s

The velocity increase by a factor of \sqrt{2}

Part b

If we mass is quadrupled we have this:

v_f = \sqrt{\frac{TL}{4m}} = \frac{1}{2} v = \frac{1}{2} *2m/s =1 m/s

The velocity decrease by a factor of 2.

Part c

If the length is quadrupled we have this:

v_f = \sqrt{\frac{4TL}{m}} = 2} v = 2 *2m/s =4m/s

The velocity increase by a factor of 2

Part d

For this case we know that the mass and the length are both quadrupled and we got:

v_f = \sqrt{\frac{4TL}{4m}} = v = 2m/s

The velocity not changes.

7 0
3 years ago
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