The initial speed of the sled at the given height is 4.85 m/s.
<h3>Initial speed of the sled</h3>
Apply the principle of conservation of energy;
K.E = P.E
¹/₂mv² = mgh
v² = 2gh
v = √2gh
where;
- h is the vertical height reached
- g is acceleration due to gravity
v = √(2 x 9.8 x 1.2)
v = 4.85 m/s
Thus, the initial speed of the sled at the given height is 4.85 m/s.
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Answer:
E_aprox = 1.003 E_real
Explanation:
In this exercise we are given the expression for the electric field of a dipole in the axis direction of the dipole
E_real = k 2q d / √(z² + d²)³
I think your equation has some errors.
In this case they indicate that d is the separation of the charges of the dipole
in the case of z »d this equations approximates
E_aprox = k 2q d/ z³
calculate the value for the two cases
E_real = k2q d / √[ ((23d)² + d²)³]
E_real = k2q d / d³ 12201
E_real = k2q 1/12201 d²
E_aprox = k2q d / (23.00d)³
E_aprox = k2q 1/12167 d²
the error between these quantities is
E_aprox / E_real = 12201 d² / 12167 d²
E_aprox / E_real = 1.003
E_aprox = 1.003 E_real
C. 10 m/s
You divide 1000 m by 100 s.
1000/100 to find the velocity
Answer:
The x component of the resultant force is -7.27N.
Explanation:
To obtain the x component of the resultant force, first we have to know the x components of the other forces. To do this, we just have to do some trigonometry:
Since both vectors are in the left side of the y-axis, they have a negative x component. So:
Finally, we sum both components to obtain the component of the resultant force:
In words, the x component of the resultant force is -7.27N.
Answer:
√(6ax)
Explanation:
Hi!
The question states that during a time t the motorcyle underwent a displacement x at constant acceleration a starting from rest, mathematically we can express it as:
x=(1/2)at^2
Then the we need to find the time t' for which the displacement is 3x
3x=(1/2)a(t')^2
Solving for t':
t'=√(6x/a)
Now, the velocity of the motorcycle as a function of time is:
v(t)=a*t
Evaluating at t=t'
v(t')=a*√(6x/a)=√(6*x*a)
Which is the final velocity
Have a nice day!
