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ki77a [65]
3 years ago
10

How do you simplify it? I know the answer is 6_/6p but I don’t really know *how* to get there.

Mathematics
1 answer:
Margarita [4]3 years ago
4 0

Answer:

The answer is

<h2>6 \sqrt{6p}</h2>

Step-by-step explanation:

<h3>\sqrt{216p}</h3>

<u>First of all factor out the perfect square</u>

From the question the perfect square is 36

We have

<h3>\sqrt{36 \times 6p}</h3>

The root of a product is equal to the product of the roots of each factor

That's

<h3>\sqrt{36 \times 6p}  =  \sqrt{36}  \times  \sqrt{6p}</h3>

Simplify

<h3>\sqrt{36}  = 6</h3>

So we have

<h3>6 \times  \sqrt{6p}</h3>

We have the final answer as

<h3>6 \sqrt{6p}</h3>

Hope this helps you

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In which diagram do angles 1 and 2 form a linear pair?
rodikova [14]

The diagram where angles 1 and 2 form a linear pair is D. A horizontal line has 1 line extending from it. Angles 1 and 2 are formed.

<h3>What is a linear pair?</h3>

It should be noted that a linear pair simply means angles that are formed when two lines intersect each other at a single point.

In this case, when a horizontal line has 1 line extending from it. Angles 1 and 2 are formed. This depicts a linear pair

In conclusion, the correct option is D.

Learn more about linear pair on:

brainly.com/question/13218054

#SPJ1

4 0
2 years ago
Segments UV and WZ are parallel with line ST intersecting both at points Q and R respectively
Zanzabum

The <em><u>correct answer</u></em> is:

Corresponding (for both blanks)

Explanation:

Corresponding angles are angles that are in the same relative position to both the parallel line they are on and the transversal.  In this case, SQU and WRS are both above the parallel line they are on and on the same side of the transversal; this makes them corresponding angles.  This also means it is the corresponding angles postulate.

3 0
3 years ago
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1. There are 6 green bulbs because
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Hope it helps you!!!!
4 0
4 years ago
I Need The Answer Plz!!
Brrunno [24]

Answer:

BCA

Step-by-step explanation:

All angles go to angles that have one curve to the angle that has the most curves, but I'm really guessing.

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4 years ago
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