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Liula [17]
3 years ago
9

A solution has a oh- = 1 x 10-5 m what are the h30 and the ph of the solution

Chemistry
2 answers:
ruslelena [56]3 years ago
6 0

Answer : The H_3O^+ concentration and the pH of the solution is, 1\times 10^{-9}M and 9 respectively.

Explanation:

First we have to calculate the pOH.

pOH=-\log [OH^-]

pOH=-\log (1\times 10^{-5})

pOH=5

Now we have to calculate the pH.

pH+pOH=14\\\\pH=14-pOH\\\\pH=14-5=9

Now we have to calculate the H_3O^+ concentration.

pH=-\log [H_3O^+]

9=-\log [H_3O^+]

[H_3O^+]=1\times 10^{-9}M

Therefore, the H_3O^+ concentration and the pH of the solution is, 1\times 10^{-9}M and 9 respectively.

Deffense [45]3 years ago
3 0

I think it's easiest to find the pOH from the given [OH-] first.

-log(1x10^-5)

pOH=5

Then find the pH.

pOH+pH=14

5+pH=14

pH=9

Then find the [H+] using the pH.

antilog(-9) (if you dont have an antilog button use 10^-9)

[H+]=1x10^-9

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