the mass number of fluorine (F) is 19
C. 19
Answer: The scientific method is an empirical method of acquiring knowledge that has characterized the development of science since at least the 17th century. It involves careful observation, applying rigorous skepticism about what is observed, given that cognitive assumptions can distort how one interprets the observation.
Explanation:
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<u>Answer:</u> The uncertainty in the velocity of oxygen molecule is ![4.424\times 10^{-5}m/s](https://tex.z-dn.net/?f=4.424%5Ctimes%2010%5E%7B-5%7Dm%2Fs)
<u>Explanation:</u>
The diameter of the molecule will be equal to the uncertainty in position.
The equation representing Heisenberg's uncertainty principle follows:
![\Delta x.\Delta p=\frac{h}{2\pi}](https://tex.z-dn.net/?f=%5CDelta%20x.%5CDelta%20p%3D%5Cfrac%7Bh%7D%7B2%5Cpi%7D)
where,
= uncertainty in position = d = ![4.50\times 10^{-5}m](https://tex.z-dn.net/?f=4.50%5Ctimes%2010%5E%7B-5%7Dm)
= uncertainty in momentum = ![m\Delta v](https://tex.z-dn.net/?f=m%5CDelta%20v)
m = mass of oxygen molecule = ![5.30\times 10^{-26}kg](https://tex.z-dn.net/?f=5.30%5Ctimes%2010%5E%7B-26%7Dkg)
h = Planck's constant = ![6.627\times 10^{-34}kgm^2/s^2](https://tex.z-dn.net/?f=6.627%5Ctimes%2010%5E%7B-34%7Dkgm%5E2%2Fs%5E2)
Putting values in above equation, we get:
![4.50\times 10^{-5}m\times 5.30\times 10^{-26}kg\times \Delta v=\frac{6.627\times 10^{-34}kgm^2/s}{2\times 3.14}\\\\\Delta v=\frac{6.627\times 10^{-34}kgm^2/s^2}{2\times 3.14\times 4.50\times 10^{-5}m\times 5.30\times 10^{-26}kg}=4.424\times 10^{-5}m/s](https://tex.z-dn.net/?f=4.50%5Ctimes%2010%5E%7B-5%7Dm%5Ctimes%205.30%5Ctimes%2010%5E%7B-26%7Dkg%5Ctimes%20%5CDelta%20v%3D%5Cfrac%7B6.627%5Ctimes%2010%5E%7B-34%7Dkgm%5E2%2Fs%7D%7B2%5Ctimes%203.14%7D%5C%5C%5C%5C%5CDelta%20v%3D%5Cfrac%7B6.627%5Ctimes%2010%5E%7B-34%7Dkgm%5E2%2Fs%5E2%7D%7B2%5Ctimes%203.14%5Ctimes%204.50%5Ctimes%2010%5E%7B-5%7Dm%5Ctimes%205.30%5Ctimes%2010%5E%7B-26%7Dkg%7D%3D4.424%5Ctimes%2010%5E%7B-5%7Dm%2Fs)
Hence, the uncertainty in the velocity of oxygen molecule is ![4.424\times 10^{-5}m/s](https://tex.z-dn.net/?f=4.424%5Ctimes%2010%5E%7B-5%7Dm%2Fs)
The spaceship does not have any gravitational pull. A spaceship can not produce its own gravity like Earth does.