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omeli [17]
3 years ago
11

An atom has the electron configuration of 1s22s22p5 how many electrons are in that atom

Chemistry
1 answer:
notsponge [240]3 years ago
7 0

Answer:

There are 9 electrons in this atom.

Explanation:

Electron configuration of this atom: 1s^2\, 2s^2\, 2p^5.

The electron orbitals of an atom are denoted as 1s, 2s, 2p, 3s, 3p, etc. At any given time, an electron in this atom is located in exactly one orbital.

The electron configuration of an atom gives the number of electrons in each orbitals of this atom.

For example, in this atom, the superscript "2" on the right of "1s" means that there are two electrons in the 1s\! orbital of this atom. Hence, 1s^2\, 2s^2\, 2p^5 would translate to:

  • The 1s orbital of this atom contains 2 electrons.
  • The 2s orbital of this atom contains 2 electrons.
  • The 2p orbitals of this atom contain 5 electrons.

Hence, there would be 2 + 2 + 5 = 9 electrons in total in this atom.

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14) The central iodine atom in the ICl4- ion has __________ nonbonded electron pairs and __________ bonded electron pairs in its
masha68 [24]

Answer:

Two non bonded electron pairs and four bonded electron pairs

Explanation:

An image of the compound as obtained from chemlibretext is attached to this answer.

The ion ICl4- ion, is an AX4E2 ion. This implies that there are four bond pairs and two lone pairs of electrons. As expected, the shape of the ion is square planar since the lone pairs are found above and below the plane of the square. This is clear from the image attached.

7 0
2 years ago
A 13.5g sample of gold is heated, then placed in a calorimeter containing 60g of water. The temperature of water increases from
sweet-ann [11.9K]

Answer:

T_i~=163.1 ºC

Explanation:

We have to start with the variables of the problem:

Mass of water = 60 g

Mass of gold = 13.5 g

Initial temperature of water= 19 ºC

Final temperature of water= 20 ºC

<u>Initial temperature of gold= Unknow</u>

Final temperature of gold= 20 ºC

Specific heat of gold = 0.13J/gºC

Specific heat of water = 4.186 J/g°C

Now if we remember the <u>heat equation</u>:

Q_H_2_O=m_H_2_O*Cp_H_2_O*deltaT

Q_A_u=m_A_u*Cp_A_u*deltaT

We can relate these equations if we take into account that <u>all heat of gold is transfer to the water</u>, so:

m_H_2_O*Cp_H_2_O*deltaT=~-~m_A_u*Cp_A_u*deltaT

Now we can <u>put the values into the equation</u>:

60~g*4.186~J/g{\circ}C*(20-19)~{\circ}C=-(13.5~g*0.13~J/g{\circ}C*(20-T_i)~{\circ}C)

Now we can <u>solve for the initial temperature of gold</u>, so:

T_i~=(\frac{60~g*4.186~J/g{\circ}C*(20-19)~{\circ}C}{13.5~g*0.13~J/g{\circ}C})+20

T_i~=163.1 ºC

I hope it helps!

5 0
3 years ago
What causes a water strider to be able to walk on water?
Lena [83]

Answer:

By repelling water, the tiny water striders stand on the water's surface and the captured airs allows them to float and move easily.  so number 2. Surface Tension.

Explanation:

The attraction between water molecules creates tension and a very delicate membrane. Water striders walk on this membrane. ... The legs have tiny hairs that repel water and capture air.

8 0
3 years ago
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How many types of biodiversity Are there
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3
Species
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8 0
3 years ago
Which of the following would not cause an increase in the pressure of a gaseous system in a container? A The container is made l
ludmilkaskok [199]

Answer:

The container is made larger

Explanation:

5 0
2 years ago
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