Answer:
96.32 %
Explanation:
Given that:
The solubility of compound in hot water = 4.35 g / 100 mL
The solubility of compound in cold water = 0.16 g / 100 mL
Which means that in 100 mL of hot water, the dissolved compound is 4.35 g and in cold water, the dissolved compound is 0.16 g
Hence, on transition, compound that will catalyze is 4.35 - 0.16 g = 4.19 g
So,
Percent recovery for re-crystallization of this compound from water= 96.32 %
To answer this question, we should give the standard free energy change of ATP to ADP conversion that is equal to 30.5 kJ/mol ATP. In this case, 2400 kcal is equal to 10041. 6 kJ. Hence, the mol of ATP produced is 329.23 mol ATP or equal to 166.93 kg ATP.
The unit cell of Aluminum is a face-centered cubic structure. This lattice unit cell consists of 4 atoms per unit cell. The volume of the unit cell is a³ where a is the length of the side of the unit cell. In terms of radius r, volume is equal to:
V = (4r/√2)³
V = (4(0.143×10⁻⁹ m)/√2)³
V = 6.62×10⁻²⁹ m³
