Ok let me explain the procedure to you:
The buffer solution is like this:
pH = pKa + log [salt]/[acid]
4 = 4.20 + log [salt] / [acid]
-0.20 = log [salt]/[acid]
If you <span>Solve for [salt]/[acid]
This gives ratio of moles.
</span><span>Take amount of acid be x L and then amount of salt will be 0.1-x
Now molarity*volume=number of moles
</span>I know that with this you will be able to get to the result. Hope this helps
Answer:
Oxygen
Explanation:
Any Hydrocarbon + Oxygen ----> Carbon Dioxide + H2O (Water vapour, gas, water)
Answer:
34.23 g.
Explanation:
<em>Molarity is defined as the no. of moles of a solute per 1.0 L of the solution.</em>
M = (no. of moles of solute)/(V of the solution (L)).
∴ M = (mass/molar mass)of C₁₂H₂₂O₁₁/(V of the solution (L)).
<em>∴ mass of C₁₂H₂₂O₁₁ = (M)(molar mass)(V of the solution (L)</em> = (1.0 M)((342.3 g/mol)/(0.10 L) = <em>34.23 g.</em>
Answer:
Overall reaction equation;
2NO(g) +Cl2(g) -----> 2NOCl (g)
Explanation:
Given
1) NO(g) + Cl2(g) → NOCl2(g)
2) NOCl2(g) + NO(g) → 2NOCl(g)
Overall reaction equation;
2NO(g) +Cl2(g) -----> 2NOCl (g)
k1= [NOCl2]
k-1= [NO] [Cl2]
k2 = [NOCl2] [NO]
Equilibrium for the first equation (reaction 1)
K= k1/k-1 = [NOCl2]/[NO] [Cl2]
Therefore
[NOCl2] = k1/k-1 [NO] [Cl2]
Rate= k2× k1/k-1 [NO]^2 [Cl2]
Rate = Koverall [NO]^2 [Cl2]
Where Koverall= k1k2/k-1
