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aalyn [17]
4 years ago
8

Help please? .....................

Mathematics
1 answer:
Ksenya-84 [330]4 years ago
8 0

2x^2+6x-10=x^2+6\qquad\text{subtract}\ x^2\ \text{and 6 from both sides}\\\\x^2+6x-16=0\\\\x^2+8x-2x-16=0\\\\x(x+8)-2(x+8)=0\\\\(x+8)(x-2)=0\iff x+8=0\ \vee\ x-2=0\\\\x+8=0\qquad\text{subtract 8 from both sides}\\\boxed{x=-8}\\\\x-2=0\qquad\text{add 2 to both sides}\\\boxed{x=2}\\\\Answer:\ \boxed{B.\ -8\ and\ C.\ 2}

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Answer:

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Step-by-step explanation:

Given:

Circumference of a pizza = 38 inches

To Find:

The Diameter of the pizza =?

Solution:

Circumference:

The distance around the edge of a circle (or any curvy shape). It is a type of perimeter.

We know that the shape of the pizza is circle.

So the given circumference is circumference of a circle.

Now,

Circumference of the circle(pizza)=2\pi r

where r is the radius of the circle

circumference of the pizza =38

Thus

2\pi r= 38

\pi r=\frac{38}{2}

\pi r=19

r=\frac{19}{3.14}

r=6.050 inches

Now,

Diameter = 2\times r

Diameter = 2\times 6.05

Diameter=12.1 inches

Rounding to the nearest tenth

Diameter=12 inches

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