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kodGreya [7K]
3 years ago
8

Classify the solid. A. tetrahedron B. dodecahedron C. octahedron D. icosahedron

Mathematics
2 answers:
Ulleksa [173]3 years ago
8 0
Tetrahedron has 4 faces so it's a pyramid, dodecahedron is 12 faces, octahedron is 8 faces, icosahedron has 20 faces. Easiest way I know to classify them
aivan3 [116]3 years ago
4 0

The answer is C. octahedron , This is because octahedron have 8 sides

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Calculate to the nearest 1/10th meter the length of the side of a 7th, 12th, and 30th hectare square plot.
Tems11 [23]

Answer and explanation:

To find : Calculate to the nearest 1/10th meter the length of the side of a 7th, 12th, and 30th hectare square plot.

Solution :

The area of the square is given by,

A=s^2 where s is the side length.

We know,  1 \text{ hectare}=10,000\ m^2

1) The area of square plot is 7 hectare.

Area in meter square is A=7\times 10000=70000\ m^2

Substitute the value in the formula,

70000=s^2

\sqrt{70000}=s

264.57=s

Side nearest to 1/10th meter is 264.8 meter.

2) The area of square plot is 12 hectare.

Area in meter square is A=12\times 10000=120000\ m^2

Substitute the value in the formula,

120000=s^2

\sqrt{120000}=s

346.41=s

Side nearest to 1/10th meter is 346.4 meter.

3) The area of square plot is 30 hectare.

Area in meter square is A=30\times 10000=300000\ m^2

Substitute the value in the formula,

300000=s^2

\sqrt{300000}=s

547.72=s

Side nearest to 1/10th meter is 547.7 meter.

5 0
2 years ago
Mike wants to fence in part of his backyard. He wants the length of the fenced-in area to be at least 20 feet long, l ≥ 20. He h
zhuklara [117]

I added a screenshot of the complete question along with the given choices.

<em><u>Answers:</u></em>

w = 10 ft and l = 50 ft ................> second option

w = 20 ft and l = 60 ft ...............> third option

w = 50 ft and l = 40 ft ...............> fifth option

<em><u>Explanation:</u></em>

<u>We are given that:</u>

length should be at least 20 ...........> length ≥ 20

equation for perimeter is : 2l + 2w ≤ 200

<u>We will check each option as follows:</u>

<u>Option 1:</u>

w = 50 ft and l = 10 ft

This option is incorrect as the proposed length is less than 20.

<u>Option 2:</u>

w = 10 ft and l = 50 ft

Since the length is greater than 20, the first condition is satisfied.

Now, we check the second condition:

2l + 2w = 2(50) + 2(10) = 100 + 20 = 120 ≤ 200

The second condition is also satisfied.

This option is correct

<u>Option 3:</u>

w = 20 ft and l = 60 ft

Since the length is greater than 20, the first condition is satisfied.

Now, we check the second condition:

2l + 2w = 2(60) + 2(20) = 120 + 40 = 160 ≤ 200

The second condition is also satisfied.

This option is correct

<u>Option 4:</u>

w = 90 ft and l = 30 ft

Since the length is greater than 20, the first condition is satisfied.

Now, we check the second condition:

2l + 2w = 2(30) + 2(90) = 60 + 180 = 240 > 200

The second condition is not satisfied.

This option is incorrect

<u>Option 5:</u>

w = 50 ft and l = 40 ft

Since the length is greater than 20, the first condition is satisfied.

Now, we check the second condition:

2l + 2w = 2(50) + 2(40) = 100 + 80 = 180 ≤ 200

The second condition is also satisfied.

This option is correct

Hope this helps :)

8 0
3 years ago
Read 2 more answers
BRAINLIEST ASAP! PLEASE. HELP ME :) I need help with part 2 of the question.
tino4ka555 [31]

Part 2:

-4a + 2 + 11a = 5a + 3 + 2a

~Combine like terms

7a + 2 = 7a + 3

~Subtract 2 to both sides

7a = 7a - 1

~Subtract 7a to both sides

0 = 1

Therefore, there are no solutions.

Best of Luck!

3 0
3 years ago
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Solve the inequality shown below.<br> -2(q-22)+q+12&gt;0
Andru [333]
<span><span><span><span>−<span>2<span>(<span>q−22</span>)</span></span></span>+q</span>+12</span>>0</span>
Step 1: Simplify both sides of the inequality.<span><span><span>
−q</span>+56</span>>0</span>
Step 2: Subtract 56 from both sides.<span><span><span><span>
−q</span>+56</span>−56</span>><span>0−56</span></span><span><span>
−q</span>><span>−56</span></span>
Step 3: Divide both sides by -1.<span><span><span>
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q<56</span>
Answer: q<56
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2 years ago
Decide if the expressions in each pair are equivalent. Explain how you know.
lilavasa [31]

Answer:

x + x + x + x is the same as 4x

because its "x four times"

5x and x+5 are not the same because x+5 in not "x five times"

5x is 5 multiplied by x.

x + 5 is 5 added to x.

7 0
1 year ago
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