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kodGreya [7K]
3 years ago
8

Classify the solid. A. tetrahedron B. dodecahedron C. octahedron D. icosahedron

Mathematics
2 answers:
Ulleksa [173]3 years ago
8 0
Tetrahedron has 4 faces so it's a pyramid, dodecahedron is 12 faces, octahedron is 8 faces, icosahedron has 20 faces. Easiest way I know to classify them
aivan3 [116]3 years ago
4 0

The answer is C. octahedron , This is because octahedron have 8 sides

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You would take the points (x1,y1) and add them into the equation y-y1=m(x-x1). In this equation m is the slope and that equals -4
6 0
2 years ago
What is the simplified form of the following expression?(x10)(x2) x8 x12 x20 x100
notka56 [123]
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6 0
2 years ago
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A ball is shot into the air using a brand new super-high-tech robotic arm to help baseball players practice catch fly balls.
stepladder [879]

Answer:

69 feet

Step-by-step explanation:

we have

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where

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t is the time in seconds

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The vertex is the maximum

so

the y-coordinate of the vertex represent the maximum height of the ball

Convert the quadratic equation into vertex form

The equation in vertex form is equal to

y=(x-h)^{2}+k

where

(h,k) is the vertex of the parabola

h(t)=-16t^{2}+64t+5

h(t)-5=-16t^{2}+64t

h(t)-5=-16(t^{2}-4t)

h(t)-5-64=-16(t^{2}-4t+4)

h(t)-69=-16(t^{2}-4t+4)

h(t)-69=-16(t-2)^{2}

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the vertex is the point (2,69)

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6 0
3 years ago
Identify the variables, the constant, the coefficients, and the exponents in the algebraic expression: 5x + 3y^{2} + 4. (The 2 i
blsea [12.9K]
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5 0
3 years ago
Bryan’s monthly electric bill is determined by adding a flat administration fee to the product of the number of kilowatt hours o
Sophie [7]
We will form the equations for this problem:
(1) 1100*y + z = 113
(2) 1500*y + z = 153
z = ? Monthly administration fee is notated with z, and that is the this problem's question.
Number of kilowatt hours of electricity used are numbers 1100 and 1500 respectively.
Cost per kilowatt hour is notated with y, but its value is not asked in this math problem, but we can calculate it anyway.
The problem becomes two equations with two unknowns, it is a system, and can be solved with method of replacement:
(1) 1100*y + z = 113
(2) 1500*y + z = 153
----------------------------
(1) z = 113 - 1100*y [insert value of z (right side) into (2) equation instead of z]:
(2) 1500*y + (113 - 1100*y) = 153
-------------------------------------------------
(1) z = 113 - 1100*y
(2) 1500*y + 113 - 1100*y = 153
------------------------------------------------
(1) z = 113 - 1100*y
(2) 400*y + 113 = 153
------------------------------------------------
(1) z = 113 - 1100*y
(2) 400*y = 153 - 113
------------------------------------------------
(1) z = 113 - 1100*y
(2) 400*y = 40
------------------------------------------------
(1) z = 113 - 1100*y
(2) y = 40/400
------------------------------------------------
(1) z = 113 - 1100*y
(2) y = 1/10
------------------------------------------------
if we insert the obtained value of y into (1) equation, we get the value of z:
(1) z = 113 - 1100*(1/10)
(1) z = 113 - 110
(1) z = 3 dollars is the monthly fee.
6 0
3 years ago
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