(a) The probability of drawing a blue marble at random from a given box is the number of blue marbles divided by the total number of marbles. We assume that the probability of selecting one of two boxes at random is 1/2 for each box.
... P(blue) = P(blue | box1)·P(box1) + P(blue | box2)·P(box2) = (3/8)·(1/2) + (4/6)·(1/2)
... P(blue) = 25/48 . . . . probability the ball is blue
(b) P(box1 | blue) = P(blue & box1)/P(blue) = (P(blue | box1)·P(box1)/P(blue)
... = ((3/8)·(1/2))/(25/48)
... P(box1 | blue) = 9/25 . . . . probability a blue ball is from box 1
Answer:
Part A)
The number of marbles that Su has at the beginning is 
The number of marbles that Bertha has at the beginning is 
Part B)
The number of marbles that Su has at the end is 
The number of marbles that Bertha has at the end is 
Step-by-step explanation:
Let
x------> number of marbles that Su has at the beginning
y------> number of marbles that Bertha has at the beginning
we know that
----> equation A
----> equation B
substitute equation A in equation B



Find the value of x

Part A) How many marbles did they EACH have at the begining?
The number of marbles that Su has at the beginning is 
The number of marbles that Bertha has at the beginning is 
Part B) How many did they EACH have at the end?

so


therefore
The number of marbles that Su has at the end is 
The number of marbles that Bertha has at the end is 
Because this equation is in slope-intercept form, we can tell exactly how it will look by checking out 3 key points.
Leading coefficient: negative, or positive.
In this case, the leading coefficient is positive, which means that the slope will be going from bottom left to upper right.
Leading coefficient = slope
In this case, the slope is 4, or 4/1, so it will be at a steep incline.
Value of constant = y-intercept.
In this case, the y-intercept is -2, which will help us narrow down our choice.
<h3><u>After reviewing the three answer choices, the most likely selection will be A, as it seems to have a slope of 4, it is positive, and it has a y-intercept of -2.</u></h3>
The answer I got is A. 25.872
Answer:
g( f(x) ) = 2x^2 + 11 (Answer choice B)
Step-by-step explanation:
g( f(x) ) involves using the function f(x) = x^2 + 6 as the input to g(x).
Here, g(x) = 2x - 1. Replace the x in g(x) by "f(x)" and the x in 2x - 1 by x^2 + 6. Then we have g( f(x) ) = 2[x^2 + 6] -1. This can be simplified, as follows:
= 2x^2 + 12 - 1, or 2x^2 + 11. This is answer choice B.