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garik1379 [7]
3 years ago
13

"How would you direct traffic in the result of a catastrophic earthquake?"

Engineering
2 answers:
11Alexandr11 [23.1K]3 years ago
8 0

Answer:

In the result of a earthquake, you should direct people into areas that are safe, such as places where the ground has not been broken up, and then tell people to get out of their cars and be careful. You should also have them carry any valuable items out of the car(if they have time), and then wait until the initial shocks and aftershocks are over, and then tell them to get back into their cars and then drive carefully and safely.

andreyandreev [35.5K]3 years ago
8 0

Answer:

You would tell people to get out of the way and stay safe.

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Which of the following best defines the term nanotechnology?
anastassius [24]
I had this quiz before. But The Answer Is C :)
4 0
3 years ago
Read 2 more answers
Consider two different versions of algorithm for finding gcd of two numbers (as given below), Estimate how many times faster it
juin [17]

Answer:

Explanation:

Step 1:

a) The formula for compute greatest advisor is

     gcd(m,n) = gcd (n,m mod n)

the gcd(31415,14142) by applying Euclid's algorithm is

    gcd(31,415,14,142) =gcd(14,142,3,131)

                                  =gcd=(3,131, 1,618)

                                   =gcd(1,618, 1,513)

                                   =gcd(1,513, 105)

                                   =gcd(105, 43)

                                    =gcd(43, 19)

                                     =gcd(19, 5)

                                      =gcd(5, 4)

                                      =gcd(4, 1)

                                      =gcd(1, 0)

                                      =1

STEP 2

b)  The number of comparison of given input with the algorithm based on  checking consecutive integers and Euclid's algorithm is

     The number of division using Euclid's algorithm =10 from part (a)

      The consecutive integer checking algorithm:

      The number of iterations =14,142 and 1 or 2 division of iteration.

        14,142 ∠= number of division∠ = 2*14,142

         Euclid's algorithm is faster by at least 14,142/10 =1400 times

          At most 2*14,142/10 =2800 times.

5 0
3 years ago
The acceleration of a particle is given by a = 2t − 10, where a is in meters per second squared and t is in seconds. Determine t
tensa zangetsu [6.8K]

Answer

given,

a = 2 t - 10

velocity function

we know,

\dfrac{dv}{dt}=a

\dfrac{dv}{dt}=(2t-10)

integrating both side

\int dv =\int (2t -10) dt

 v = t² - 10 t + C

at t = 0   v = 3

so, 3 = 0 - 0 + C

     C = 3

Velocity function is equal to v = t² - 10 t + 3

Again we know,

\dfrac{dx}{dt}=v

\dfrac{dx}{dt}=(t^2-10t + 3)

integrating both side

\int dx =\int (t^2-10t + 3)dt

x = \dfrac{t^3}{3}- 10\dfrac{t^2}{2} + 3 t + C

now, at t= 0 s = -4

-4 = \dfrac{0^3}{3}- 10\dfrac{0^2}{2} + 0 + C

C = -4

So,

x = \dfrac{t^3}{3}- 10\dfrac{t^2}{2} + 3 t-4

Position function is equal to x = \dfrac{t^3}{3}- 10\dfrac{t^2}{2} + 3 t-4

8 0
3 years ago
This is an essential safety procedure that protects workers from injury while working on or near electrical circuits and equipme
Mice21 [21]

Answer:

Option B

Lockout/ Tagout

Explanation:

lockout and tagout is a safety procedure used in most industries and work places. This ensures that during any maintenance work, that dangerous machines are properly shut off and not able to be started up again prior to the completion of maintenance or repair work.

The procedure includes:

1. Turns off and disconnects the machinery or equipment from its energy source(s) before performing service or maintenance.

2. The authorized employee(s) either lock or tag the energy-isolating device(s) to prevent the release of hazardous energy.

8 0
4 years ago
A scale model is 4th the size of the pump. Determine the power ratio of the pump and its scale model if the ratio of the heads i
vredina [299]

Given:

size of scale model = 4(size of pump)

power ratio of pump and scale model = 5:1

Solution:

Let the diameter of scale model and pump be d_{s} and d_{p} respectively

and head be  H_{s} and  H_{p} respectively

Now, power, P is given as a function of head(H) and dischagre(Q)

P = \rho gQH                  (1)

From eqn (1):

P \propto QH

and

QH \propto \sqrt{H}D^{2}

So,

P \propto H^{\frac{3}{2}} D^{2}

Therefore,

\frac{P_{s}}{P_{p}} = \frac{D_{s}^{2} H_{s}^{\frac{3}{2}}}{D_{p}^{2} H_{p}^{\frac{3}{2}}}

\frac{P_{s}}{P_{p}} = \frac{D_{s}^{2} H_{s}^{\frac{3}{2}}}{D_{p}^{2} H_{p}^{\frac{3}{2}}}

\frac{P_{s}}{P_{p}} = \frac{1^{2}\times 5^{\frac{3}{2}}}{4^{2}\times 1^{\frac{3}{2}}}

\frac{P_{s}}{P_{p}} = \frac{5\sqrt{5}}{16}

{P_{s}}:{P_{p}} = {5\sqrt{5}}:{16}

8 0
3 years ago
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