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katrin2010 [14]
3 years ago
13

That there is evidence of electrical failure given that there was a gas leak. Enter your answer in accordance to the item b) of

the question statementEntry field with incorrect answer 0.55 (c) That there is evidence of a gas leak given that there is evidence of electrical failure.

Engineering
2 answers:
butalik [34]3 years ago
8 0

Answer:

a) 0.84

b) 0.643

c) 0.931

Explanation:

Given:

The complete missing question is as follows.

" The maintenance firm has gathered the following information regarding the failure mechanism for 100 air conditioning systems:

                                                                  Evidence of Gas Leaks

                                                                     Yes                    No

Evidence of Electrical Failure    Yes           54                       4

                                                     No            30                     12

Find:

a)The failure involves a gas leak

b)That there is evidence of electrical failure given that there was a gas leak.

c)That there is evidence of a gas leak given that there is evidence of electrical failure.

Solution:

                    "Refer to the attachment for the solution"

givi [52]3 years ago
5 0

Answer:

See attachment below

Explanation:

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Answer:

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An ideal Carnot engine extracts of heat from a high-temperature reservoir at 1200 during each cycle, and rejects heat to a low-t
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Answer:

efficiency of the engine is 0.4167

Explanation:

given data

T high = 1200 K

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solution

we get here efficiency that is express as

efficiency  = 1 - \frac{T\ low}{T \ high }    .........................1

put here value of both temperature we get efficiency  

efficiency  = 1 - \frac{700}{1200}

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3 years ago
Water flows in a tube that has a diameter of D= 0.1 m. Determine the Reynolds number if the average velocity is 10 diameters per
Cloud [144]

Answer:

a) Re_{D} = 111896.745, b) Re_{D} = 1.119\times 10^{-7}

Explanation:

a) The Reynolds number for the water flowing in a circular tube is:

Re_{D} = \frac{\rho\cdot v\cdot D}{\mu}

Let assume that density and dynamic viscosity at 25 °C are 997\,\frac{kg}{m^{3}} 0.891\times 10^{-3}\,\frac{kg}{m\cdot s}, respectively. Then:

Re_{D}=\frac{(997\,\frac{kg}{m^{3}} )\cdot (1\,\frac{m}{s} )\cdot (0.1\,m)}{0.891\times 10^{-3}\,\frac{kg}{m\cdot s} }

Re_{D} = 111896.745

b) The result is:

Re_{D}=\frac{(997\,\frac{kg}{m^{3}} )\cdot (10^{-6}\,\frac{m}{s} )\cdot (10^{-7}\,m)}{0.891\times 10^{-3}\,\frac{kg}{m\cdot s} }

Re_{D} = 1.119\times 10^{-7}

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Answer:

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