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2 years ago

10

While servicing a vehicle, you retrieve the diagnostic code P0401, "EGR (exhaust gas recirculatior flow insufficient." Which of

these is the most likely cause?

1 answer:

n200080 [17]2 years ago

3 0

Answer: Clogged EGR ports or passages

Explanation: The clogging causes insufficient flow.

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What is the advantage of having the engine in the front of the car?

Ugo [173]

Answer:

<h2>No advantages bro!!</h2>

Explanation:

hehehehe DONTTTT report my answer

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3 years ago

Read 2 more answers

A large retirement village has a total retail employment of 120. All 1600 of the households in this village consist of two nonwo

polet [3.4K]

Answer:

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Explanation:

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4 years ago

A fair die is thrown, What is the probability gained if you are told that 4 will

Semmy [17]

Answer:

1/6

Explanation:

A dice has 6 sides, the probability of 4 appearing is 1/6.

7 0

3 years ago

The thrust F of a screw propeller is known to depend upon the diameter d,speed of advance \nu ,fluid density p, revolution per s

musickatia [10]

Answer:

<em>screw thrust = ML</em> $T^{-2}$ <em> </em>

Explanation:

thrust of a screw propeller is given by the equation = p $V^{2}$ $D^{2}$ x $\frac{ND}{V}$ Re

where,

D is diameter

V is the fluid velocity

p is the fluid density

N is the angular speed of the screw in revolution per second

Re is the Reynolds number which is equal to puD/μ

where p is the fluid density

u is the fluid velocity, and

μ is the fluid viscosity = kg/m.s = M $L^{-1}$ $T^{-1}$

<em>Reynolds number is dimensionless so it cancels out</em>

The dimensions of the variables are shown below in MLT

diameter is m = L

speed is in m/s = L $T^{-1}$

fluid density is in kg/ $m^{3}$ = M $L^{-3}$

N is in rad/s = L $L^{-1}$ $T^{-1}$ =

If we substitute these dimensions in their respective places in the equation, we get

thrust = M $L^{-3}$ $(LT^{-1}) ^{2}$ $L^{2}$ $\frac{T^{-1} L}{LT^{-1} }$

= M $L^{-3}$ $L^{2}$ $T^{-2}$

<em>screw thrust = ML</em> $T^{-2}$ <em> </em>

This is the dimension for a force which indicates that thrust is a type of force

6 0

3 years ago

Carbon dioxide at 20°C flows in a pipe at a rate of 0.005 kg/s. Determine the minimum diameter required if the flow is laminar (

Vesna [10]

Answer:

the required diameter is 0.344 m

Explanation:

given data:

flow is laminar

flow of carbon dioxide Q = 0.005 Kg/s

for flow to be laminar, Reynold's number must be less than 2300 for pipe flow and it is given as

$\frac{\rho VD}{\mu }$

arrange above equation for diameter

\frac{\rho Q D}{\mu A }<2300

dynamic density of carbon dioxide = 1.47× $10^{-5}$ Pa sec

density of carbon dioxide is 1.83 kg/m³

$\frac{1.83\times 0.0056\times D}{1.47\times 10^{-5}\times \frac{\pi}{4} \times D^{2} }$

$\frac{1.83\times 0.0056}{1.47\times 10^{-5}\times \frac{\pi}{4} \times 2300}= D$

D = 0.344 m

4 0

3 years ago