Answer:
Check the explanation
Explanation:
As Granitetown requires 5000 IP address and the starting IP address is 192.172.0.0 , we have to perform subnetting using number of hosts required
Number of IP address required by Granitetown=4000
Number of hosts bits =
2n -2= 5000
n=13 (approximately)
Number of hosts bits are 13 therefore subnet prefix =(32-13)=19
We have used 32 because IP address is of 32-bit
Subnet mask corresponding to /19 = 255.255.224.0
Starting IP address (given)= 192.172.0.0
Now to calculate last IP address of the subnet, OR operation will be performed between First IP address of the subnet and !Netmask
First IP address of subnet ( in binary) =
11000000.10101100.00000000.00000000
OR
00000000.00000000.00011111.11111111 (!Netmask)
11000000.10101100.000 11111.11111111 (result)
Converting result into decimal gives IP address 192.172.31.255 which will be the broadcast IP address of the subnet therefore
Last usable IP address = 192.172.31.254
Now, bedrock requires 2000 IP address
Therefore number of host bits are =
2n -2 =2000
n=10 (approximately)
Number of hosts bits required are 10
Therefore Netmask prefix = (32 -10) =22
Now, using the next subnet for bedrock therefore the first IP address of subnet will be 192.172.32.0
Now, similarly calculating last IP address of subnet
First IP address in binary =
11000000.10101100.00100000.00000000
OR
00000000.00000000.00000011.11111111 (!Netmask)
11000000.10101100.00100011.11111111 (result)
Now, result in decimal = 192.172.35.255
Therefore ,
Broadcast address of subnet =192.172.35.255
Last usable IP address =192.172.35.254
