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Gnom [1K]
3 years ago
14

Thulium-167 has a half-life of 9.25 days. If you begin with 48 grams of thulium-167, how much of the original isotope will remai

n after 37 days?
Chemistry
1 answer:
fgiga [73]3 years ago
4 0

Answer:

2.3125g

Explanation:

Half-life referred to the time required for a quantity to reduce to half of its initial value, It used to calculate how unstable atoms undergo, or the period of time and atom can survive, radioactive decay.

Given:

t(1/2)= 9.25days

Initial mass of Thulium-167 = 48grams

We need to calculate the remaining amount after 37days.

Since we know that 1 half life = 9.25 days

Then 37 days means ( 37/9.25) half lives

37days means 4 half life

That means the 38grams of Thulium-167 will be halved by 4 times.

Then the ratio between the initial Amount and the amount remaining after 37 days can be calculated as. 0.5^(4)

= 37days × 0.5^(4)

= 2.3125g

the remaining amount of Thallium-167 after 37days is 2.3125g

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4 years ago
Which element has the lowest ionization energy?
Andreas93 [3]

Answer:

Cs

Explanation:

This question is formatted oddly, but I understand the gist of it. Essentially, even if the periodic table is cut off by one row and missing the lanthanides and actinides, basic rules of the table still apply.

Remember the general trend of ionization energy: <u>the farther to the right and the farther up, the higher the ionization energy.</u>

As an example, fluorine is the "t-rex" of the elements because it's so electronegative that it hoards electrons, and that means it's hard to take its electrons away, which gives it a high ionization energy.

Out of the given choices, cesium Cs has the lowest ionization energy because it's so far to the left and so low. You can just nab an electron and it won't even mind too much.

<em>Why not the other answer choices? </em>Bromine is a halogen (so it's on the far right of the table) and it's fairly high up, so its ionization energy is much too high. Argon is a noble gas, so it's so stable that it hates it when someone tries to take an electron away; it has a very high ionization energy. Nickel, likewise, is a transition metal, so it's not the answer either.

8 0
3 years ago
Read 2 more answers
When 1 mol CS2(l) forms from its elements at 1 atm and 25°C, 89.7 kJ of heat is absorbed, and it takes 27.7 kJ to vaporize 1 mol
Kitty [74]

Answer:

There is 117.4 kJ of heat absorbed

Explanation:

<u>Step 1: </u>Data given

Number of moles CS2 = 1 mol

Temperature = 25° = 273 +25 = 298 Kelvin

Heat absorbed = 89.7 kJ

It takes 27.7 kJ to vaporize 1 mol of the liquid

<u>Step 2:</u> Calculate the heat that is absorbed

C(s) + 2S(s) → CS2(l)    ΔH = 89.7 kJ  (positive since heat is absorbed)

CS2(l) → CS2(g)           ΔH = 27.7 kJ  (positive since heat is absorbed)

We should balance the equations, before summing, but since they are already balanced, we don't have to change anything.

C(s) + 2S(s)---> CS2 (g)

ΔH = 89.7 + 27.7 = 117.4 kJ

There is 117.4 kJ of heat absorbed

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How many moles of co2 are produced when 5.70 mol of ethane are burned in an excess of oxygen
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